Math Problem Statement

Given are the data for two variables, x and y. Do not round your intermediate calculations.

xi: 6 11 15 18 20 yi: 6 8 12 20 30

a. Develop an estimated regression equation for these data by computing b1 and b0 (to 3 decimals). Enter negative values as negative numbers.

Solution

To develop the estimated regression equation for these data, we need to find the slope b1b_1 and the y-intercept b0b_0 using the following formulas:

1. Slope b1b_1

The formula for b1b_1 (the slope of the regression line) is:

b1=nxiyixiyinxi2(xi)2b_1 = \frac{n \sum{x_i y_i} - \sum{x_i} \sum{y_i}}{n \sum{x_i^2} - (\sum{x_i})^2}

2. Intercept b0b_0

The formula for b0b_0 (the intercept of the regression line) is:

b0=yib1xinb_0 = \frac{\sum{y_i} - b_1 \sum{x_i}}{n}

Where:

  • nn is the number of data points
  • xix_i and yiy_i are the data points for the variables xx and yy

Let’s calculate these values step by step.

Given Data:

xi:6,11,15,18,20x_i: 6, 11, 15, 18, 20 yi:6,8,12,20,30y_i: 6, 8, 12, 20, 30

Step 1: Compute the necessary sums

  • xi=6+11+15+18+20=70\sum{x_i} = 6 + 11 + 15 + 18 + 20 = 70
  • yi=6+8+12+20+30=76\sum{y_i} = 6 + 8 + 12 + 20 + 30 = 76
  • xi2=62+112+152+182+202=36+121+225+324+400=1106\sum{x_i^2} = 6^2 + 11^2 + 15^2 + 18^2 + 20^2 = 36 + 121 + 225 + 324 + 400 = 1106
  • xiyi=6(6)+11(8)+15(12)+18(20)+20(30)=36+88+180+360+600=1264\sum{x_i y_i} = 6(6) + 11(8) + 15(12) + 18(20) + 20(30) = 36 + 88 + 180 + 360 + 600 = 1264

Step 2: Calculate the slope b1b_1

Using the formula for b1b_1:

b1=5(1264)(70)(76)5(1106)(70)2b_1 = \frac{5(1264) - (70)(76)}{5(1106) - (70)^2} b1=6320532055304900b_1 = \frac{6320 - 5320}{5530 - 4900} b1=10006301.587b_1 = \frac{1000}{630} \approx 1.587

Step 3: Calculate the intercept b0b_0

Now we can compute b0b_0 using the formula:

b0=76(1.587)(70)5b_0 = \frac{76 - (1.587)(70)}{5} b0=76111.095b_0 = \frac{76 - 111.09}{5} b0=35.0957.018b_0 = \frac{-35.09}{5} \approx -7.018

Final Estimated Regression Equation:

y^=7.018+1.587x\hat{y} = -7.018 + 1.587x

So the estimated regression equation is:

y^=7.018+1.587x\hat{y} = -7.018 + 1.587x


Would you like more details or clarifications on any of these steps? Here are some follow-up questions that might interest you:

  1. How can we interpret the slope and intercept of the regression equation in real-life terms?
  2. What is the method to assess the accuracy of the regression equation?
  3. How can we compute the correlation coefficient from the regression equation?
  4. How would adding more data points affect the regression equation?
  5. What assumptions are made when applying linear regression?

Tip: When working with regression, always check for outliers or unusual data points that could skew your results!

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Data Analysis

Formulas

b1 = (n Σ(xi yi) - Σxi Σyi) / (n Σ(xi^2) - (Σxi)^2)
b0 = (Σyi - b1 Σxi) / n
Estimated Regression Equation: ŷ = b0 + b1x

Theorems

Least Squares Regression

Suitable Grade Level

College-Level Statistics or Advanced High School