Math Problem Statement

The table below gives the age and bone density for five randomly selected women. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting a woman's bone density based on her age. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Age 42 51 55 64 65 Bone Density 355 329 328 324 312 Table

Step 2 of 6 : Find the estimated y-intercept. Round your answer to three decimal places.

Solution

To find the estimated y-intercept (b0b_0) of the regression line, we need to follow these steps:

1. Calculate the regression coefficients

The equation of the regression line is given as:

y^=b0+b1x\hat{y} = b_0 + b_1x

Where:

  • b0b_0 is the y-intercept (what we're solving for),
  • b1b_1 is the slope of the regression line,
  • y^\hat{y} is the predicted bone density,
  • xx is the age.

Step 1: Compute the slope b1b_1 using the formula:

b1=nxiyixiyinxi2(xi)2b_1 = \frac{n\sum{x_iy_i} - \sum{x_i}\sum{y_i}}{n\sum{x_i^2} - (\sum{x_i})^2}

Where:

  • nn is the number of data points (5 in this case),
  • xix_i and yiy_i are the values of age and bone density for each data point.

Step 2: Calculate the y-intercept b0b_0 using the formula:

b0=yib1xinb_0 = \frac{\sum{y_i} - b_1 \sum{x_i}}{n}

Now, let's break down the data:

  • x=[42,51,55,64,65]x = [42, 51, 55, 64, 65]
  • y=[355,329,328,324,312]y = [355, 329, 328, 324, 312]

We need to compute the following sums:

  • xi\sum{x_i}
  • yi\sum{y_i}
  • xiyi\sum{x_iy_i}
  • xi2\sum{x_i^2}

Let me calculate all of this now. numpy as np

Data

x = np.array([42, 51, 55, 64, 65]) y = np.array([355, 329, 328, 324, 312])

Calculations

n = len(x) sum_x = np.sum(x) sum_y = np.sum(y) sum_xy = np.sum(x * y) sum_x_squared = np.sum(x ** 2)

Calculate b1 (slope)

b1 = (n * sum_xy - sum_x * sum_y) / (n * sum_x_squared - sum_x ** 2)

Calculate b0 (y-intercept)

b0 = (sum_y - b1 * sum_x) / n

b0, b1The estimated y-intercept (b0b_0) of the regression line is approximately 413.671 (rounded to three decimal places).

If you need more details or further calculations, feel free to ask!


Here are some related questions that may help you dive deeper into this concept:

  1. How do you interpret the slope (b1b_1) in the context of this problem?
  2. What does the correlation coefficient tell us about the relationship between age and bone density?
  3. How do you calculate the standard error of the regression line?
  4. Why is it important to check the statistical significance of the correlation coefficient before using a regression model for prediction?
  5. What assumptions must be met for linear regression to be appropriate in this scenario?

Tip: To interpret the y-intercept meaningfully, think about what the predicted bone density would be if the woman’s age were zero. However, since age zero doesn’t make sense in this context, it's mainly useful for calculations.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Correlation
Slope and Y-Intercept

Formulas

yˆ = b0 + b1x
b1 = (n∑xiy_i - ∑xi∑yi) / (n∑xi² - (∑xi)²)
b0 = (∑yi - b1∑xi) / n

Theorems

Least Squares Method
Correlation and Regression Analysis

Suitable Grade Level

Grades 11-12