Math Problem Statement

A town's population has been growing linearly. In 2003 the population was 43,000. The population has been growing by 1200 people each year. Write an equation for the population, P, x years after 2003. Use the formula to find the population in 2009.

Solution

We are given the following information:

  • The town's population in 2003 was 43,000.
  • The population has been growing by 1,200 people each year.

1. Writing the Equation:

We need to express the population PP as a function of xx, where xx represents the number of years after 2003.

The general equation for linear growth is:

P=P0+rxP = P_0 + r \cdot x

Where:

  • P0P_0 is the initial population (in 2003, this was 43,000),
  • rr is the rate of growth per year (1,200 people),
  • xx is the number of years after 2003.

So, the equation becomes:

P=43000+1200xP = 43000 + 1200x

2. Finding the Population in 2009:

To find the population in 2009, we need to substitute x=20092003=6x = 2009 - 2003 = 6 into the equation.

P=43000+12006P = 43000 + 1200 \cdot 6

Now, calculating the population:

P=43000+7200=50200P = 43000 + 7200 = 50200

So, the population in 2009 is 50,200.

Would you like further explanation or details on how this was solved?

Relative Questions:

  1. How do you derive the slope for linear population growth models?
  2. What happens if the population decreases by a certain amount each year?
  3. How would the equation change if the town started with a different population in 2003?
  4. Can the population growth be modeled using an exponential function instead of a linear one?
  5. How would you calculate the population in any future year using this formula?

Tip:

Always double-check units (years, people, rates) to ensure consistency when plugging values into the formula.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Growth
Algebra

Formulas

Linear growth formula: P = P0 + r * x

Theorems

-

Suitable Grade Level

Grades 8-10