Math Problem Statement
A town's population has been growing linearly. In 2003, the population was 65000, and the population has been growing by 700 people each year.
Write an equation for the population x years after 2003.
Solution
The town's population is growing linearly, so we can use the equation of a straight line in the form of:
Where:
- is the population years after 2003,
- is the rate of population growth per year,
- is the initial population at , which corresponds to the year 2003.
Given:
- In 2003, the population was 65,000, so .
- The population has been growing by 700 people per year, so .
Now, substitute these values into the equation:
Thus, the equation for the population years after 2003 is:
Would you like more details or further clarification?
Here are five related questions to consider:
- What will the population be in 2025?
- How many years will it take for the population to reach 80,000?
- How would the equation change if the growth rate doubled?
- What if the town's population decreased by 200 people per year instead of increasing?
- How does linear growth differ from exponential population growth?
Tip: In linear growth, the rate of change is constant, making it easier to predict future values compared to non-linear growth.
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Math Problem Analysis
Mathematical Concepts
Algebra
Linear Equations
Formulas
Linear equation formula: P(x) = mx + b
Theorems
Slope-Intercept Form
Suitable Grade Level
Grades 6-8
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