Math Problem Statement

A town's population has been growing linearly. In 2003, the population was 65000, and the population has been growing by 700 people each year.

Write an equation for the population x years after 2003.

Solution

The town's population is growing linearly, so we can use the equation of a straight line in the form of:

P(x)=mx+bP(x) = mx + b

Where:

  • P(x)P(x) is the population xx years after 2003,
  • mm is the rate of population growth per year,
  • bb is the initial population at x=0x = 0, which corresponds to the year 2003.

Given:

  • In 2003, the population was 65,000, so b=65,000b = 65,000.
  • The population has been growing by 700 people per year, so m=700m = 700.

Now, substitute these values into the equation:

P(x)=700x+65,000P(x) = 700x + 65,000

Thus, the equation for the population xx years after 2003 is:

P(x)=700x+65,000P(x) = 700x + 65,000

Would you like more details or further clarification?

Here are five related questions to consider:

  1. What will the population be in 2025?
  2. How many years will it take for the population to reach 80,000?
  3. How would the equation change if the growth rate doubled?
  4. What if the town's population decreased by 200 people per year instead of increasing?
  5. How does linear growth differ from exponential population growth?

Tip: In linear growth, the rate of change is constant, making it easier to predict future values compared to non-linear growth.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Linear equation formula: P(x) = mx + b

Theorems

Slope-Intercept Form

Suitable Grade Level

Grades 6-8