The function provided is $f(x) = 3x + 4 + 2$, which simplifies to:

$f(x) = 3x + 6$

However, the question doesn't specify any domain or range conditions. If you're looking for the domain of the function $f(x) = 3x + 6$, it's a linear function, which means that it is defined for all real numbers.

Domain:

Since this is a linear function with no restrictions (like square roots or denominators), the domain is all real numbers, which in interval notation is:

$\text{Domain: } (-\infty, \infty)$

Range:

Because the output of a linear function can also take any value, the range is also all real numbers:

$\text{Range: } (-\infty, \infty)$

If you were asked to enter the domain or range in interval notation, it would be:

$(-\infty, \infty)$

Would you like more details or clarification? Here are some related questions to deepen your understanding:

1. What is the slope and y-intercept of the function $f(x) = 3x + 6$?
2. How does the graph of $f(x) = 3x + 6$ compare to $f(x) = x$?
3. Can a linear function ever have a restricted domain?
4. How can you determine the range of a function?
5. What are the transformations applied to $f(x) = x$ to get $f(x) = 3x + 6$?

Tip: When finding domain and range for linear functions, remember they generally cover all real numbers unless there are specific constraints like division by zero or square roots of negative numbers.