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To solve the system of linear equations using substitution, we are given:

\[
3x + y = -9 \quad (1)
\]
\[
y = 5x + 7 \quad (2)
\]

### Steps:

1. **Substitute equation (2) into equation (1):**
   Since \( y = 5x + 7 \), replace \( y \) in equation (1) with \( 5x + 7 \):
   \[
   3x + (5x + 7) = -9
   \]
   
2. **Simplify the equation:**
   \[
   3x + 5x + 7 = -9
   \]
   \[
   8x + 7 = -9
   \]
   
3. **Solve for \( x \):**
   Subtract 7 from both sides:
   \[
   8x = -9 - 7
   \]
   \[
   8x = -16
   \]
   Divide by 8:
   \[
   x = -2
   \]

4. **Substitute \( x = -2 \) into equation (2) to find \( y \):**
   \[
   y = 5(-2) + 7
   \]
   \[
   y = -10 + 7
   \]
   \[
   y = -3
   \]

### Solution:
The solution to the system of equations is \( x = -2 \) and \( y = -3 \). Therefore, the solution is \( (-2, -3) \).

Would you like further clarification or additional details?

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Here are five related questions to expand on this topic:

1. How do you solve a system of equations using elimination instead of substitution?
2. What are the conditions for a system of linear equations to have no solution?
3. How can graphing be used to solve a system of linear equations?
4. What is the difference between dependent and independent systems of equations?
5. How do you verify if a solution to a system of equations is correct?

**Tip:** Always double-check your substitution to ensure accuracy when solving systems of equations.

Solve the system of linear equations by substitution: 3x + y = -9 and y = 5x + 7.

Learn how to solve a system of linear equations using substitution. This problem involves the equations 3x + y = -9 and y = 5x + 7, and is solved step by step to find the values of x and y. Suitable for students in Grades 8-10.

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