The given equation is in slope-intercept form, which is $y = mx + b$, where:

• $m$ is the slope of the line.
• $b$ is the y-intercept (the point where the line crosses the y-axis).

For the equation $y = -\frac{1}{3}x + 1$:

• The slope $m = -\frac{1}{3}$. This means the line decreases by 1 unit for every 3 units it moves to the right.
• The y-intercept $b = 1$. So the line crosses the y-axis at $(0, 1)$.

Would you like more details or have any questions?

Here are 5 related questions for further practice:

1. What is the x-intercept of the line $y = -\frac{1}{3}x + 1$?
2. How would you graph the line using its slope and y-intercept?
3. What is the equation of a line parallel to $y = -\frac{1}{3}x + 1$?
4. How does changing the slope to $-\frac{2}{3}$ affect the line?
5. What is the equation of a line perpendicular to $y = -\frac{1}{3}x + 1$?

Tip: The slope tells you how steep a line is and whether it rises or falls as you move along the x-axis.