The equation given in the image is:

$y = -\frac{1}{3}x - 9$

This is the equation of a straight line in slope-intercept form, $y = mx + b$, where:

• $m = -\frac{1}{3}$ is the slope of the line.
• $b = -9$ is the y-intercept, which means the line crosses the y-axis at $y = -9$.

How to graph this equation:

1. Start with the y-intercept: The point where the line crosses the y-axis is at $(0, -9)$.
2. Use the slope: The slope $m = -\frac{1}{3}$ means that for every 3 units you move to the right (positive direction along the x-axis), the line goes down by 1 unit (negative direction along the y-axis).
3. Plot another point: From $(0, -9)$, move 3 units right and 1 unit down. This gives you the next point at $(3, -10)$.
4. Draw the line: Connect the points with a straight line, extending it across the graph.

Would you like more detailed steps on graphing, or any other questions related to this problem?

5 Related Questions:

1. How do you find the slope of a line from two points?
2. What is the significance of the y-intercept in a graph?
3. How would the graph change if the slope were positive instead of negative?
4. Can you rewrite the equation in standard form $Ax + By = C$?
5. How can you calculate the x-intercept of this line?

Tip: When graphing, always start with the y-intercept, and then use the slope to find additional points for a more accurate line!