The question asks us to write a linear equation for a line with a slope of $-8$ and a y-intercept of $-3$.

Solution:

The general form of a linear equation in slope-intercept form is:

$y = mx + b$ Where:

• $m$ is the slope.
• $b$ is the y-intercept.

Given:

• $m = -8$
• $b = -3$

Substitute these values into the equation:

$y = -8x - 3$

Final Answer:

The linear equation is:

$y = -8x - 3$

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Related Questions:

1. What is the slope-intercept form of a linear equation?
2. How do you find the slope and y-intercept from a graph?
3. How can you rewrite $y = -8x - 3$ in standard form?
4. If a line has a slope of $-8$, what is the slope of a line perpendicular to it?
5. How would you graph the equation $y = -8x - 3$?

Tip:

Always identify the slope ($m$) and the y-intercept ($b$) to write the equation quickly in slope-intercept form.