The question asks to write an equation in slope-intercept form for the line with a slope of -3 and a y-intercept of -1.

The slope-intercept form of a line is given by:

$y = mx + b$

Where:

• $m$ is the slope of the line.
• $b$ is the y-intercept.

Given:

• Slope $m = -3$
• Y-intercept $b = -1$

Substituting these values into the slope-intercept form equation:

$y = -3x - 1$

So, the equation of the line is:

$y = -3x - 1$

Would you like more details or explanations? Here are five follow-up questions to expand your understanding:

1. How would the equation change if the slope were positive?
2. What is the significance of the y-intercept in this equation?
3. How can you determine the slope and y-intercept from a graph?
4. What does the graph of this equation look like?
5. How do you find the equation of a line given two points?

Tip: The slope tells you how steep the line is, and the y-intercept shows where the line crosses the y-axis!