The problem asks to write the equation of a line in slope-intercept form, given a slope of 8 and a y-intercept of -3.

The slope-intercept form of a line is:

$y = mx + b$

where:

• $m$ is the slope,
• $b$ is the y-intercept.

Given:

• $m = 8$ (slope),
• $b = -3$ (y-intercept),

Substitute these values into the slope-intercept equation:

$y = 8x - 3$

Thus, the equation of the line is:

$y = 8x - 3$

Would you like more details or have any questions?

Here are 5 related questions you can explore:

1. How do you graph a line using slope-intercept form?
2. What does the slope represent in real-world applications?
3. How would the equation change if the slope were negative?
4. How do you find the x-intercept of a line given its equation?
5. What happens if the y-intercept is zero?

Tip: When graphing a line, the y-intercept tells you where the line crosses the y-axis, and the slope determines how steep the line is.