Math Problem Statement

If a linear cost and revenue function are defined by C(x) = 15x + 100 and R(x) = 22x, how many items must be sold to break even?

Solution

The problem asks to find how many items must be sold to break even given the cost function C(x)=15x+100C(x) = 15x + 100 and the revenue function R(x)=22xR(x) = 22x.

To break even, the cost must equal the revenue. Therefore, we set C(x)=R(x)C(x) = R(x):

15x+100=22x15x + 100 = 22x

Now, solve for xx:

22x15x=10022x - 15x = 100

7x=1007x = 100

x=100714.29x = \frac{100}{7} \approx 14.29

Since the question asks for the number of items sold (which must be a whole number), round up to the nearest whole number:

x=15x = 15

Therefore, 15 items must be sold to break even.

Would you like more details on any step?

Here are 5 related questions you might find helpful:

  1. How do we define the break-even point in business?
  2. What does the slope of the cost function represent in this scenario?
  3. How does the fixed cost of 100 affect the break-even point?
  4. What would happen if the price per item (in revenue) changes?
  5. How would we calculate profit if more than 15 items are sold?

Tip: Always check whether rounding is necessary when working with quantities of items, as fractional items usually don't make sense in practical terms.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Break-even Analysis

Formulas

C(x) = 15x + 100
R(x) = 22x

Theorems

Break-even point occurs when cost equals revenue.

Suitable Grade Level

Grades 9-10