Math Problem Statement
Solve for all
Solution
Let's break down the graph and solve each part of the question step by step.
Observing the Graph at :
- The function seems to have a discontinuity at .
- There's a jump discontinuity, which means the left-hand limit () and the right-hand limit () are different.
Now, let's compute each value:
1. :
This is the limit as approaches 1 from the left. Looking at the graph, as approaches 1 from the left side (from values like ), the function tends to a value of 3.
Thus,
2. :
This is the limit as approaches 1 from the right. From the graph, as approaches 1 from the right side (from values like ), the function tends to a value of -4.
Thus,
3. :
The overall limit at exists only if both the left-hand and right-hand limits are equal. Since and , these are not equal, so the limit does not exist.
Thus,
4. :
The value of the function at is given by the point at . From the graph, there is a solid dot at corresponding to the value -2.
Thus,
Summary of Answers:
Let me know if you want more details or have further questions!
Here are 5 related questions:
- What is the difference between jump and removable discontinuities?
- How would the graph change if ?
- Can a function have a value at even if does not exist?
- How do you calculate the limit at a point of continuity versus discontinuity?
- How do you graphically identify the left-hand and right-hand limits?
Tip: When analyzing a discontinuous function, always check the left-hand and right-hand limits separately to identify the type of discontinuity!
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Math Problem Analysis
Mathematical Concepts
Limits
Discontinuity
Left-hand and Right-hand Limits
Formulas
Limit definition: \( \lim_{x \to c} f(x) \)
Left-hand limit: \( \lim_{x \to c^-} f(x) \)
Right-hand limit: \( \lim_{x \to c^+} f(x) \)
Theorems
Limit existence condition: \( \lim_{x \to c^-} f(x) = \lim_{x \to c^+} f(x) \)
Discontinuity conditions: jump discontinuity, removable discontinuity
Suitable Grade Level
Grade 10-12
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