Math Problem Statement

Solve for all

Solve for the limits and the value of the function f(x) when x = 1, based on the graph provided.

Solution

Let's break down the graph and solve each part of the question step by step.

Observing the Graph at x=1x = 1:

  • The function seems to have a discontinuity at x=1x = 1.
  • There's a jump discontinuity, which means the left-hand limit (limx1f(x)\lim_{x \to 1^-} f(x)) and the right-hand limit (limx1+f(x)\lim_{x \to 1^+} f(x)) are different.

Now, let's compute each value:

1. limx1f(x)\lim_{x \to 1^-} f(x):

This is the limit as xx approaches 1 from the left. Looking at the graph, as xx approaches 1 from the left side (from values like x=0.5,0.9x = 0.5, 0.9), the function tends to a value of 3.

Thus, limx1f(x)=3\lim_{x \to 1^-} f(x) = 3

2. limx1+f(x)\lim_{x \to 1^+} f(x):

This is the limit as xx approaches 1 from the right. From the graph, as xx approaches 1 from the right side (from values like x=1.1,1.5x = 1.1, 1.5), the function tends to a value of -4.

Thus, limx1+f(x)=4\lim_{x \to 1^+} f(x) = -4

3. limx1f(x)\lim_{x \to 1} f(x):

The overall limit at x=1x = 1 exists only if both the left-hand and right-hand limits are equal. Since limx1f(x)=3\lim_{x \to 1^-} f(x) = 3 and limx1+f(x)=4\lim_{x \to 1^+} f(x) = -4, these are not equal, so the limit does not exist.

Thus, limx1f(x)=DNE (Does Not Exist)\lim_{x \to 1} f(x) = \text{DNE (Does Not Exist)}

4. f(1)f(1):

The value of the function at x=1x = 1 is given by the point at x=1x = 1. From the graph, there is a solid dot at x=1x = 1 corresponding to the value -2.

Thus, f(1)=2f(1) = -2

Summary of Answers:

  1. limx1f(x)=3\lim_{x \to 1^-} f(x) = 3
  2. limx1+f(x)=4\lim_{x \to 1^+} f(x) = -4
  3. limx1f(x)=DNE\lim_{x \to 1} f(x) = \text{DNE}
  4. f(1)=2f(1) = -2

Let me know if you want more details or have further questions!

Here are 5 related questions:

  1. What is the difference between jump and removable discontinuities?
  2. How would the graph change if limx1f(x)=limx1+f(x)\lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x)?
  3. Can a function have a value at x=1x = 1 even if limx1f(x)\lim_{x \to 1} f(x) does not exist?
  4. How do you calculate the limit at a point of continuity versus discontinuity?
  5. How do you graphically identify the left-hand and right-hand limits?

Tip: When analyzing a discontinuous function, always check the left-hand and right-hand limits separately to identify the type of discontinuity!

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Math Problem Analysis

Mathematical Concepts

Limits
Discontinuity
Left-hand and Right-hand Limits

Formulas

Limit definition: \( \lim_{x \to c} f(x) \)
Left-hand limit: \( \lim_{x \to c^-} f(x) \)
Right-hand limit: \( \lim_{x \to c^+} f(x) \)

Theorems

Limit existence condition: \( \lim_{x \to c^-} f(x) = \lim_{x \to c^+} f(x) \)
Discontinuity conditions: jump discontinuity, removable discontinuity

Suitable Grade Level

Grade 10-12