Math Problem Statement

1	Determine if the function is continuous at the following points. Justify your conclusions with explanations. Look at the graph
β€’	π‘₯=0
β€’	π‘₯=1
β€’	π‘₯=2
Determine if the function is continuous at the following points based on the graph: x = 0, x = 1, x = 2.

Solution

Let's analyze the function's continuity at x=0x = 0, x=1x = 1, and x=2x = 2 based on the graph.

1. Continuity at x=0x = 0:

  • Limit from the left: As xβ†’0βˆ’x \to 0^-, the graph approaches f(0)=1f(0) = 1.
  • Limit from the right: As xβ†’0+x \to 0^+, the graph also approaches f(0)=1f(0) = 1.
  • Function value: The function at x=0x = 0 is closed (solid circle) and equals 1.

Since the left-hand limit (LHL) equals the right-hand limit (RHL), and both are equal to the function value, the function is continuous at x=0x = 0.

2. Continuity at x=1x = 1:

  • Limit from the left: As xβ†’1βˆ’x \to 1^-, the graph approaches f(1)=2f(1) = 2.
  • Limit from the right: As xβ†’1+x \to 1^+, the graph approaches f(1)=0f(1) = 0.
  • Function value: There is an open circle at x=1x = 1, indicating the function is undefined at that point.

Since the left-hand limit does not equal the right-hand limit, and the function is not defined at x=1x = 1, the function is not continuous at x=1x = 1.

3. Continuity at x=2x = 2:

  • Limit from the left: As xβ†’2βˆ’x \to 2^-, the graph approaches f(2)=0f(2) = 0.
  • Limit from the right: As xβ†’2+x \to 2^+, the graph also approaches f(2)=0f(2) = 0.
  • Function value: The function at x=2x = 2 is closed (solid circle) and equals 0.

Since the left-hand limit equals the right-hand limit, and both are equal to the function value, the function is continuous at x=2x = 2.

Summary:

  • The function is continuous at x=0x = 0 and x=2x = 2.
  • The function is not continuous at x=1x = 1 due to a jump discontinuity and being undefined.

Would you like more details or have any further questions?

Here are 5 relative questions for further understanding:

  1. What conditions must be met for a function to be continuous at a point?
  2. What is the difference between a removable discontinuity and a jump discontinuity?
  3. How does the function behave near x=βˆ’2x = -2, based on the graph?
  4. How do limits help in determining the continuity of a function?
  5. How would the function change if the point at x=1x = 1 was closed?

Tip: When checking for continuity at a point, always ensure the left-hand limit, right-hand limit, and function value exist and are equal.

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Math Problem Analysis

Mathematical Concepts

Continuity
Limits
Piecewise Functions

Formulas

Left-hand limit: lim_{x→c^-} f(x)
Right-hand limit: lim_{x→c^+} f(x)
Function value: f(c)

Theorems

Continuity at a point: A function is continuous at x = c if the left-hand limit, right-hand limit, and function value exist and are equal.

Suitable Grade Level

Grades 9-12