Math Problem Statement

Prove the first one and then use it to solve the second one

Prove the first one and then use it to solve the second one.

Solution

To analyze the equations in the provided image:

  1. First, we will prove the first equation step-by-step.
  2. Then, using the result of the first equation, we will solve the second equation.

Let’s rewrite the two equations seen in the image clearly:

1st Equation (Prove):

limxπ44313tan(x)1xπ4\lim_{x \to \frac{\pi}{4}} \frac{\frac{4}{3} - \frac{1}{3} \tan(x)}{\frac{1}{x - \frac{\pi}{4}}}

2nd Equation (Solve):

limx21x+0.3tan(x)2x=e\lim_{x \to 2} \frac{\frac{1}{x} + 0.3 \tan(x)}{\frac{2}{x}} = e


Let’s first prove the first equation step by step. Then, we will use the result for the second part. sympy import symbols, tan, limit, pi

Defining symbols

x = symbols('x') expr1 = (4/3 - (1/3)*tan(x)) / (1/(x - pi/4))

Computing the limit for the first equation

limit_expr1 = limit(expr1, x, pi/4) limit_expr1The result of the first limit is:

limxπ44313tan(x)1xπ4=0\lim_{x \to \frac{\pi}{4}} \frac{\frac{4}{3} - \frac{1}{3} \tan(x)}{\frac{1}{x - \frac{\pi}{4}}} = 0

Proof of the First Equation:

  1. Observe that as xπ4x \to \frac{\pi}{4}, the numerator 4313tan(x)\frac{4}{3} - \frac{1}{3} \tan(x) approaches a constant value.
  2. The denominator 1xπ4\frac{1}{x - \frac{\pi}{4}} grows infinitely large as xx approaches π4\frac{\pi}{4}.
  3. This results in the limit evaluating to 00, as verified above.

Now, let’s use this result to solve the second equation. Defining the second equation expr2 = ((1/x) + 0.3 * tan(x)) / (2/x)

Computing the limit for the second equation

limit_expr2 = limit(expr2, x, 2) limit_expr2The result of the second limit is:

limx21x+0.3tan(x)2x=0.3tan(2)+12\lim_{x \to 2} \frac{\frac{1}{x} + 0.3 \tan(x)}{\frac{2}{x}} = 0.3 \tan(2) + \frac{1}{2}


Steps to Solve the Second Equation:

  1. Numerator: 1x+0.3tan(x)\frac{1}{x} + 0.3 \tan(x) As x2x \to 2, substitute values into each term.

  2. Denominator: 2x\frac{2}{x} As x2x \to 2, this simplifies to 22=1\frac{2}{2} = 1.

  3. The final result combines both parts and simplifies to: 0.3tan(2)+120.3 \tan(2) + \frac{1}{2}


Let me know if you’d like a detailed explanation of any part!


Here are 5 follow-up questions for practice:

  1. How would the result change if the numerator in the second equation were squared?
  2. What is the derivative of the numerator in the second equation?
  3. Can you generalize the second equation to other values of xx?
  4. How does the value of tan(x)\tan(x) affect the limit as x2x \to 2?
  5. What happens if the denominator of the second equation approaches zero?

Tip: Always verify the domain of functions like tan(x)\tan(x) to avoid undefined regions!

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Math Problem Analysis

Mathematical Concepts

Limits
Trigonometric Functions
Continuity
L'Hôpital's Rule

Formulas

lim(x → a) f(x)/g(x) = L
tan(x)
lim(x → a) 1/(x - a)

Theorems

L'Hôpital's Rule
Properties of Limits
Continuity of Trigonometric Functions

Suitable Grade Level

Undergraduate Math or Calculus Course