Math Problem Statement

limxx1/x=elimxlnxx=e0=1\lim_{x \to \infty} x^{1/x} = e^{\lim_{x \to \infty} \frac{\ln x}{x}} = e^0 = 1

Solution

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Math Problem Analysis

Mathematical Concepts

Limits
Exponential Functions
Logarithmic Functions

Formulas

L'Hopital's Rule: \lim_{x \to \infty} \frac{f(x)}{g(x)} = \lim_{x \to \infty} \frac{f'(x)}{g'(x)}
Natural Logarithm: \ln(a^b) = b \ln(a)

Theorems

L'Hopital's Rule
Properties of Exponential and Logarithmic Functions

Suitable Grade Level

Grades 11-12 (Pre-Calculus and Calculus)