Math Problem Statement
lim x tends to 1 x^x - x/x-1-logx
Solution
We are tasked with finding the limit:
Let’s proceed step by step.
Step 1: Analyze as
Recall that: At : Thus, when , which suggests that the expression might have an indeterminate form. We'll need to apply L'Hopital's Rule to this part.
Step 2: Apply L'Hopital’s Rule to
To apply L'Hopital's Rule, we differentiate the numerator and denominator.
-
Numerator derivative :
- Derivative of :
- Derivative of is .
So the derivative of the numerator is:
-
Denominator derivative : The derivative of is simply 1.
Therefore, applying L'Hopital's Rule: At , this becomes:
Step 3: Handle the logarithmic term
Now, we need to handle the term in the limit. As , .
Step 4: Combine the results
We found that both the terms and tend to 0 as . Therefore, the overall limit is:
Final Answer:
Would you like more details or have any questions?
Here are 5 related questions:
- How can we prove is differentiable at all points?
- What are some other ways to compute limits involving indeterminate forms?
- How does L'Hopital’s Rule work for higher-order indeterminate forms?
- Can we apply Taylor series expansion around to approximate the limit?
- How does the behavior of logarithmic functions compare to power functions near singularities?
Tip: L'Hopital’s Rule is useful when both the numerator and denominator tend to 0 or infinity; always check if these conditions hold before applying.
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Math Problem Analysis
Mathematical Concepts
Limits
L'Hopital's Rule
Logarithmic Functions
Exponential Functions
Formulas
lim_{x \to 1} (x^x - x)/(x - 1)
x^x = e^{x \log x}
L'Hopital's Rule: \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}
Theorems
L'Hopital's Rule
Exponential Function Properties
Logarithmic Function Properties
Suitable Grade Level
Grades 11-12
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