Math Problem Statement

The coordinates of the vertices of the triangle shown are P (2,13) , Q (7,1) and R (2,1) .

What is the length of segment PQ in units?

Solution

To find the length of segment PQPQ, we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Given the coordinates:

  • P=(2,13)P = (2, 13)
  • Q=(7,1)Q = (7, 1)

Plug these into the distance formula:

d=(72)2+(113)2d = \sqrt{(7 - 2)^2 + (1 - 13)^2} d=52+(12)2d = \sqrt{5^2 + (-12)^2} d=25+144d = \sqrt{25 + 144} d=169d = \sqrt{169} d=13d = 13

The length of segment PQPQ is 13 units.

Would you like more details or have any questions?

Here are five related questions to deepen your understanding:

  1. How do you find the midpoint of segment PQPQ?
  2. What is the length of segment PRPR?
  3. How can the slope of segment PQPQ be calculated?
  4. What is the perimeter of triangle PQRPQR?
  5. How can you verify if triangle PQRPQR is a right triangle?

Tip: Always remember to double-check your subtraction of coordinates in distance calculations to avoid sign errors.

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Math Problem Analysis

Mathematical Concepts

Geometry
Distance Formula
Coordinate Geometry

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem (used in the distance formula)

Suitable Grade Level

Grades 7-10