Math Problem Statement

Consider the set Pa(1,2,3,4,5) under the partial ordering R=((1, 1), (1,2), (1,3), (1,4), (1,5),(2,2)(2,3),(2,5),(3,3),(3,5)(4,4),(4,5),(5,5)). The minimum number of ordered pairs that need to be added to R to make (P,R) a lattice is zero.

Solution

Let's break down the problem.

We are given a set P={1,2,3,4,5}P = \{1, 2, 3, 4, 5\} and a partial ordering RR consisting of the following relations:

R={(1,1),(1,2),(1,3),(1,4),(1,5),(2,2),(2,3),(2,5),(3,3),(3,5),(4,4),(4,5),(5,5)}R = \{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 2), (2, 3), (2, 5), (3, 3), (3, 5), (4, 4), (4, 5), (5, 5)\}

Key Definitions:

  1. Partial Ordering: A partial order is a binary relation that is reflexive, antisymmetric, and transitive.
  2. Lattice: A lattice is a partially ordered set in which every pair of elements has both a least upper bound (join) and a greatest lower bound (meet).

Step-by-step analysis:

  1. Check the partial order properties:

    • Reflexivity: Each element is related to itself, as we see (1,1),(2,2),(3,3),(4,4),(5,5)(1, 1), (2, 2), (3, 3), (4, 4), (5, 5).
    • Antisymmetry: If aba \leq b and bab \leq a, then a=ba = b. The given pairs comply with this.
    • Transitivity: If aba \leq b and bcb \leq c, then aca \leq c. Based on the given pairs, this holds (e.g., 121 \leq 2 and 232 \leq 3 implies 131 \leq 3).
  2. Check if the relation defines a lattice:

    • Greatest Lower Bound (GLB) or meet: For every pair of elements aa and bb, there should be a greatest element cc such that cac \leq a and cbc \leq b.
    • Least Upper Bound (LUB) or join: For every pair of elements aa and bb, there should be a least element dd such that ada \leq d and bdb \leq d.

To form a lattice, we need to ensure that for every pair of elements in the set PP, both the meet and join exist.

  1. Examine the structure: The given ordering of elements seems to already define a structure where:
    • 1 is the least element (since 121 \leq 2, 131 \leq 3, 141 \leq 4, 151 \leq 5).
    • 5 is the greatest element (since 252 \leq 5, 353 \leq 5, 454 \leq 5).
    • Intermediate relationships such as 2352 \leq 3 \leq 5 and 454 \leq 5 further support this.

Thus, this structure already allows for the meet and join for any pair of elements. Therefore, no additional pairs need to be added.

Conclusion:

The minimum number of ordered pairs that need to be added to RR to make (P,R)(P, R) a lattice is indeed zero. This means that (P,R)(P, R) is already a lattice.


Would you like more details or have any questions?
Here are 5 related questions to explore further:

  1. What is the difference between a partial order and a total order?
  2. How can we construct the Hasse diagram of the given relation RR?
  3. What conditions must a partially ordered set satisfy to be considered a lattice?
  4. Can a lattice be finite or infinite, and how does that affect its structure?
  5. How do meet and join operations behave in lattices with more complex sets?

Tip: Always verify reflexivity, antisymmetry, and transitivity when checking if a relation is a partial order.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Partial Ordering
Lattice Theory
Set Theory

Formulas

-

Theorems

Lattice Meet and Join Conditions
Partial Order Properties: Reflexivity, Antisymmetry, Transitivity

Suitable Grade Level

College-level Discrete Mathematics