Math Problem Statement

Let A1 = {1, 2, 3, 4, 5, 6} be ordered by the relation 'x divides y.' Prove that A1 is a poset and draw the Hasse diagram.

Solution

Let's break down the problem step by step.

The set A1={1,2,3,4,5,6}A_1 = \{ 1, 2, 3, 4, 5, 6 \} is ordered by the relation "x divides y." This is a divisibility relation where xyx \leq y if and only if xx divides yy (denoted as xyx \mid y).

1. Proving that A1A_1 is a poset:

A poset (partially ordered set) must satisfy three properties:

  • Reflexivity: Every element divides itself, i.e., xxx \mid x for all xA1x \in A_1.
  • Antisymmetry: If xyx \mid y and yxy \mid x, then x=yx = y.
  • Transitivity: If xyx \mid y and yzy \mid z, then xzx \mid z.

Let's check each property for A1A_1:

  1. Reflexivity: Clearly, for every xA1x \in A_1, xxx \mid x. Hence, reflexivity holds.
  2. Antisymmetry: If xyx \mid y and yxy \mid x, the only way this can happen in terms of divisibility is if x=yx = y. Hence, antisymmetry holds.
  3. Transitivity: If xyx \mid y and yzy \mid z, then xzx \mid z because divisibility is transitive. Hence, transitivity holds.

Since all three properties are satisfied, A1A_1 is a poset.

2. Drawing the Hasse Diagram:

The Hasse diagram is a graphical representation of the poset, where each element is represented as a node, and there is an edge between two elements xx and yy if xyx \mid y and there is no intermediate element zz such that xzyx \mid z \mid y. This eliminates redundant edges, capturing only the direct divisibility relationships.

  • Elements of A1A_1: 1,2,3,4,5,61, 2, 3, 4, 5, 6
  • Divisibility relationships:
    • 11 divides every number: 12,13,14,15,161 \mid 2, 1 \mid 3, 1 \mid 4, 1 \mid 5, 1 \mid 6
    • 242 \mid 4 and 262 \mid 6
    • 363 \mid 6

Now, let's create the Hasse diagram.

We will use the following relations for the diagram:

  • 11 divides all elements.
  • 242 \mid 4, 262 \mid 6.
  • 363 \mid 6.
  • There are no other direct divisibility relations.

The Hasse diagram will look something like this:

    6
   / \
  4   3
   \ /
    2
    |
    1

This is the Hasse diagram for the poset defined by the divisibility relation on the set A1={1,2,3,4,5,6}A_1 = \{ 1, 2, 3, 4, 5, 6 \}.

Would you like more details or have any questions?


Here are 5 questions to consider:

  1. What is the difference between a poset and a totally ordered set?
  2. How would the Hasse diagram change if we included more numbers in the set, such as 12 or 15?
  3. How do we represent reflexivity and transitivity in a Hasse diagram?
  4. Can a poset have cycles in its Hasse diagram? Why or why not?
  5. How do we generalize this divisibility poset for larger sets of numbers?

Tip: To create a Hasse diagram, remember to only draw edges for direct relations and omit reflexive and transitive connections.

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Math Problem Analysis

Mathematical Concepts

Poset
Divisibility
Partially Ordered Set
Hasse Diagram

Formulas

-

Theorems

Reflexivity
Antisymmetry
Transitivity

Suitable Grade Level

Undergraduate level