Math Problem Statement

Let p be the product of the first 100 positive odd integers. Find the largest integer k such that P is divisble by 3 to the power k.

Solution

We are tasked with finding the largest integer kk such that the product of the first 100 positive odd integers is divisible by 3k3^k.

Let PP denote the product of the first 100 odd integers:

P=1×3×5××199P = 1 \times 3 \times 5 \times \cdots \times 199

To determine the largest integer kk such that 3k3^k divides PP, we need to count the number of factors of 3 in the product PP. Specifically, we are interested in how many times 3 appears as a factor in the numbers from 1 to 199.

Step 1: Identify multiples of

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisibility
Prime Factorization

Formulas

Divisibility rule for powers of prime numbers
Formula for product of odd integers

Theorems

Legendre's Theorem for prime factorization

Suitable Grade Level

Grades 11-12