Math Problem Statement

Q23: Ball A is dropped from the top of a building. At the same instant, ball B is thrown vertically upwards from the ground. When the balls collide, they are moving in opposite directions and the speed of A is twice the speed of B. The collision occurred at α/β of the height of the building. What is the value of α + β? Q24: A particle moves in a straight line with constant acceleration 'a'. The displacements of the particle from the origin at t = t1, t = t2, and t = t3 are s1, s2, and s3 respectively. If t1, t2, t3 are in A.P. with common difference d and displacements are in G.P., find the value of n (any number) if a = ((√s3 - √s1)^2) / (nd^2). Q25: A particle with instantaneous velocity v = (2î + 3ĵ + xk̂) m/s and instantaneous acceleration a = 3î - 4.5ĵ - 6k̂ m/s^2. If the path of the particle is a straight line, then magnitude of 5x/4 is:

Solution

Let's go through each question individually.


Q23

Problem: Ball AA is dropped from the top of a building, and at the same time, ball BB is thrown upwards from the ground. When they collide, they move in opposite directions, and the speed of AA is twice the speed of BB. The collision occurs at αβ\frac{\alpha}{\beta} of the building's height. Find α+β\alpha + \beta.

Solution Outline:

  1. Let the height of the building be HH.
  2. The motion of each ball can be described using the equations of motion under gravity.
  3. Define vAv_A and vBv_B as the velocities of balls AA and BB at the point of collision.
  4. Use the given condition vA=2vBv_A = 2v_B and the fact that they collide at a certain height αβH\frac{\alpha}{\beta} H.
  5. Set up equations based on these conditions and solve for α+β\alpha + \beta.

Q24

Problem: A particle moves in a straight line with constant acceleration aa. The displacements of the particle from the origin at t=t1t = t_1, t=t2t = t_2, and t=t3t = t_3 are s1s_1, s2s_2, and s3s_3 respectively. If t1t_1, t2t_2, and t3t_3 are in arithmetic progression with a common difference dd and displacements are in geometric progression, find the value of nn (any number) if a=(s3s1)2nd2.a = \frac{\left(\sqrt{s_3} - \sqrt{s_1}\right)^2}{nd^2}.

Solution Outline:

  1. Use the conditions of arithmetic and geometric progression for the times and displacements.
  2. Apply equations of motion to relate s1s_1, s2s_2, and s3s_3 to the acceleration aa.
  3. Use the formula given for aa and solve for nn.

Q25

Problem: A particle with instantaneous velocity v=(2i^+3j^+xk^)m/s\vec{v} = (2\hat{i} + 3\hat{j} + x\hat{k}) \, \text{m/s} and instantaneous acceleration a=3i^4.5j^6k^m/s2\vec{a} = 3\hat{i} - 4.5\hat{j} - 6\hat{k} \, \text{m/s}^2. If the path of the particle is a straight line, find the magnitude of xx such that it is 54\frac{5}{4}.

Solution Outline:

  1. For the particle to move in a straight line, the velocity and acceleration vectors must be parallel.
  2. This implies that v×a=0\vec{v} \times \vec{a} = 0.
  3. Set up the cross product condition, solve for xx, and then calculate the magnitude of xx as specified.

Would you like me to provide detailed solutions for each question?


Here are some related questions for further practice:

  1. How do we calculate the relative velocity between two objects moving in opposite directions?
  2. What conditions must be met for two moving objects to collide at a certain point?
  3. How does the arithmetic progression of time intervals affect the displacement of an accelerating object?
  4. How can we determine if two vectors are parallel based on their components?
  5. What are the steps to solve problems involving motion with constant acceleration in multiple dimensions?

Tip: Always analyze the conditions of parallelism or perpendicularity when dealing with vector motion questions.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Equations of Motion
Arithmetic Progression (A.P.)
Geometric Progression (G.P.)
Vectors
Parallelism in Vectors

Formulas

Equations of motion under gravity: s = ut + 0.5at^2
Geometric progression relationship for displacements
Condition for straight-line motion: v × a = 0
Formula for acceleration a = ((√s3 - √s1)^2) / (nd^2)

Theorems

Properties of Arithmetic and Geometric Progressions
Conditions for Parallelism in Vectors

Suitable Grade Level

Grade 12