Math Problem Statement

Now let's consider the particle in the next time step. At the previous step, the situation was: [t = 0.5\text{s}] an [x]-coordinate of [3] a velocity of [5] units per second in the [x] direction an acceleration of [-2] units per second per second in the [x] direction Particle with velocity vector pointing right and acceleration vector pointing left If we update our simulation every [0.5\text{s}]: What is its [x]-coordinate at [t = 1\text{s}]? units What is its velocity in the [x]-direction at [t = 1\text{s}]? units per second What is its acceleration in the [x]-direction at [t = 1\text{s}]? units per second per second

Solution

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Math Problem Analysis

Mathematical Concepts

Kinematics
Constant Acceleration

Formulas

Position equation: x(t) = x(0) + v(0) * t + 0.5 * a * t^2
Velocity equation: v(t) = v(0) + a * t
Acceleration equation: a(t) = constant

Theorems

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Suitable Grade Level

High School