Math Problem Statement

solve this carefully. Only round up values up to 2 decimal places

A block of mass M = 12.0 kg slides to the right with speed u = 6.00 m/s across a rough horizontal surface. A light rope tugs on the block with a force T = 12.0 N oriented α = 35.0° above the horizontal. The coefficient of kinetic friction between the block and the surface is μ_k = 0.420. Solve the following: (A) When the block has moved 2.50 m from its initial position, what is the block’s speed? (B) When the block has stopped, how far has it traveled from its initial position? (C) When the block has stopped, how much work has friction done to the block?

Solution

We are given a problem involving a block with mass M=12.0kgM = 12.0 \, \text{kg}, moving to the right with an initial speed u=6.00m/su = 6.00 \, \text{m/s} on a rough horizontal surface. The block is being pulled by a rope exerting a force T=12.0NT = 12.0 \, \text{N} at an angle α=35\alpha = 35^\circ above the horizontal. The coefficient of kinetic friction between the block and the surface is μk=0.420\mu_k = 0.420.

We are asked to solve the following:

Part A:

When the block has moved 2.50 m from its initial position, what is its speed?

Part B:

When the block has stopped, how far has it traveled from its initial position?

Part C:

When the block has stopped, how much work has friction done to the block?


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Math Problem Analysis

Mathematical Concepts

Newton's Second Law
Kinematics
Work-Energy Theorem
Frictional Forces

Formulas

Newton's Second Law: F = ma
Kinematic equation: v^2 = u^2 + 2as
Frictional force: f_k = μ_k * N
Work done by a force: W = F * d * cos(θ)

Theorems

Work-Energy Theorem: The work done by all forces equals the change in kinetic energy.

Suitable Grade Level

Undergraduate Physics