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The problem involves a block of mass \(6.0 \, \text{kg}\) being pushed against a wall with a force of \(100 \, \text{N}\) at an angle of \(60^\circ\). There is both static and kinetic friction involved, and we need to determine the friction acting on the block after 1 second.

### Step 1: Break Down the Forces
- **Normal force**: The force pushing the block against the wall comes from the horizontal component of the applied force:
  \[
  F_{\text{normal}} = 100 \, \text{N} \times \cos(60^\circ) = 100 \times 0.5 = 50 \, \text{N}.
  \]
  This normal force determines the frictional forces.

- **Gravitational force**: The weight of the block is:
  \[
  F_{\text{gravity}} = mg = 6.0 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 58.8 \, \text{N}.
  \]
  This force acts downward.

### Step 2: Determine Static Friction Maximum
Static friction acts to prevent the block from sliding, and its maximum value is:
\[
f_{\text{static, max}} = \mu_s F_{\text{normal}} = 0.50 \times 50 \, \text{N} = 25 \, \text{N}.
\]
This is the maximum force static friction can exert. If the gravitational force exceeds this, the block will start to slide.

### Step 3: Analyze the Situation
- The downward gravitational force is \(58.8 \, \text{N}\), which is greater than the maximum static friction of \(25 \, \text{N}\).
- This means that static friction cannot hold the block, and it will start sliding downward.

### Step 4: Kinetic Friction Acting on the Block
Once the block begins to move, kinetic friction will act against the motion (upward, as the block is sliding downward). The kinetic friction is given by:
\[
f_{\text{kinetic}} = \mu_k F_{\text{normal}} = 0.30 \times 50 \, \text{N} = 15 \, \text{N}.
\]
So, the kinetic friction acts **upward** as the block slides down the wall.

### Conclusion:
The correct answer is:
- **Kinetic friction acts upward on the block.**

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Do you want further details or have any questions about this solution? Here are some related questions:

1. How is the normal force affected if the angle of the applied force changes?
2. What would happen if the coefficient of static friction were higher?
3. How do you calculate the acceleration of the block once it starts sliding?
4. What is the difference between static and kinetic friction in general?
5. How would the friction change if the block were pushed upward at an angle instead of downward?

**Tip**: Always resolve forces into their perpendicular components to analyze problems involving friction and inclines!

A 6.0 kg block initially at rest is pushed against a wall by a 100 N force as shown. The coefficient of kinetic friction is 0.30 while the coefficient of static friction is 0.50. What is true of the friction acting on the block after a time of 1 second?

Explore how static and kinetic friction act on a 6.0 kg block pushed against a wall with a 100 N force. This detailed solution uses Newton's Laws and friction formulas to explain the forces acting after 1 second. Suitable for high school physics students (Grades 10-12).

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