To find the acceleration during the time interval from 0 to 1 second, we can use the formula for acceleration:

$a = \frac{{\Delta v}}{{\Delta t}}$

where:

• $\Delta v$ is the change in velocity,
• $\Delta t$ is the change in time.

From the table:

• At $t = 0 \, \text{s}$, the velocity is $0 \, \text{m/s}$,
• At $t = 1 \, \text{s}$, the velocity is $2 \, \text{m/s}$.

Thus, the change in velocity is:

$\Delta v = 2 \, \text{m/s} - 0 \, \text{m/s} = 2 \, \text{m/s}$

The time interval is:

$\Delta t = 1 \, \text{s} - 0 \, \text{s} = 1 \, \text{s}$

Now, applying these values to the acceleration formula:

$a = \frac{{2 \, \text{m/s}}}{{1 \, \text{s}}} = 2 \, \text{m/s}^2$

Thus, the acceleration for the time interval 0 to 1 second is:

$\boxed{2 \, \text{m/s}^2}$

The correct answer is C. 2 m/s².

Would you like any further details or clarifications?

Related Questions:

1. How is average velocity calculated over a time interval?
2. What is the formula for displacement in uniformly accelerated motion?
3. How do we calculate the final velocity in uniformly accelerated motion?
4. What is the physical meaning of negative acceleration?
5. How is instantaneous acceleration different from average acceleration?

Tip:

Remember that acceleration is the rate of change of velocity. If velocity changes by the same amount each second, the acceleration is constant.