To calculate the acceleration from the repeated measurements, we can use the formula of uniform acceleration based on velocity and time:

$a = \frac{\Delta v}{\Delta t}$

Where:

• $v$ is the velocity in meters per second (m/s),
• $t$ is the time in seconds (s),
• $a$ is the acceleration in meters per second squared (m/s²).

From the table in the image, you have several pairs of velocity ($v$) and time ($t$) measurements. I will calculate the acceleration for each pair of consecutive data points using the formula:

$a = \frac{v_2 - v_1}{t_2 - t_1}$

Let me compute the accelerations from these values.It seems there is a division by zero error because the first two time values are identical ($t_1 = t_2 = 1.90$ seconds). This results in a time difference of zero, which makes the calculation undefined for that pair.

I will skip the cases where the time difference is zero and calculate the acceleration for the other data points. Let me do this.The valid calculated accelerations between consecutive data points are as follows:

1. Between the second and third pair of values: $-0.286 \, \text{m/s}^2$,
2. Between the third and fourth pair of values: $-0.250 \, \text{m/s}^2$,
3. Between the fourth and fifth pair of values: $-0.250 \, \text{m/s}^2$.

These negative values indicate that the object is decelerating.

Would you like more details or have any further questions?

Here are 5 related questions you might find helpful:

1. How does negative acceleration affect an object's motion?
2. Can acceleration be constant in this scenario?
3. How is average acceleration calculated with multiple data points?
4. What would the graph of velocity vs. time look like?
5. How can we interpret changes in velocity for non-uniform acceleration?

Tip: When dealing with real data, it's common to encounter measurement errors or repeated values, so it's important to handle such cases carefully.