To find the acceleration of the car during the interval AB on the velocity-time graph, we need to calculate the rate of change of velocity over that interval. This can be done using the slope formula:

$\text{Acceleration} = \frac{\Delta \text{velocity}}{\Delta \text{time}}$

From the graph:

• Point A corresponds to $t = 0$ seconds and $v = 0$ m/s.
• Point B corresponds to $t = 4$ seconds and $v = 20$ m/s.

Using the slope formula, we calculate the acceleration as follows: $\text{Acceleration} = \frac{20 \, \text{m/s} - 0 \, \text{m/s}}{4 \, \text{s} - 0 \, \text{s}} = \frac{20 \, \text{m/s}}{4 \, \text{s}} = 5 \, \text{m/s}^2$

This means the acceleration of the car during the interval AB is $5 \, \text{m/s}^2$, which isn't one of the options provided. If this value seems unexpected based on the options, please double-check that the points A and B are correctly identified or consider if there's a scale factor on the graph that wasn't accounted for.

Would you like more details on this calculation or have any other questions? Here are some topics we could explore further:

1. How to determine velocity from a velocity-time graph.
2. How to calculate the total distance traveled using a velocity-time graph.
3. The relationship between acceleration, velocity, and displacement.
4. Explanation of uniform acceleration.
5. Understanding the area under a velocity-time graph.

Tip: When working with graphs, always check if the axes are scaled uniformly or if any scaling factors are applied.