To calculate the distance traveled during the second second, we'll need to use the following formulas from kinematics:

1. Displacement formula (for uniformly accelerated motion): $s = ut + \frac{1}{2} a t^2$ where:

   • $s$ is the displacement,
   • $u$ is the initial velocity,
   • $a$ is the acceleration,
   • $t$ is the time.

2. The total distance traveled during the second second is the difference between the distance traveled in two seconds and the distance traveled in one second: $\text{Distance in second second} = s(2) - s(1)$

We'll need some initial conditions such as the initial velocity ($u$) and acceleration ($a$).

Could you please provide the values for $u$ (initial velocity) and $a$ (acceleration), or should I assume it's a common case (e.g., starting from rest with constant acceleration)?

Let me know how you'd like to proceed!