Math Problem Statement

E(X)=2/3 (theta)

Theta hat (MOM) is 3/2 - 1/n (sum from 1 to n of Xi)

Is theta hat unibiased ?

Solution

To check if θ^\hat{\theta} (the method of moments estimator) is unbiased, we need to verify if its expected value equals the true parameter θ\theta. That is, we want to check if E(θ^)=θE(\hat{\theta}) = \theta.

Given:

  • E(X)=23θE(X) = \frac{2}{3} \theta, the population mean.
  • The method of moments estimator (MOM) for θ\theta is given as:

θ^=321ni=1nXi\hat{\theta} = \frac{3}{2} - \frac{1}{n} \sum_{i=1}^{n} X_i

Step 1: Find the expected value of θ^\hat{\theta}

The estimator θ^\hat{\theta} involves the sample mean:

θ^=321ni=1nXi\hat{\theta} = \frac{3}{2} - \frac{1}{n} \sum_{i=1}^{n} X_i

We can rewrite this as:

θ^=32X\hat{\theta} = \frac{3}{2} - \overline{X} where X\overline{X} is the sample mean:

X=1ni=1nXi\overline{X} = \frac{1}{n} \sum_{i=1}^{n} X_i

Now, let's compute the expected value of θ^\hat{\theta}:

E(θ^)=E(32X)E(\hat{\theta}) = E\left(\frac{3}{2} - \overline{X}\right)

Since the expectation of a constant is the constant itself, and the expectation of the sample mean X\overline{X} is the population mean E(X)E(X), we have:

E(θ^)=32E(X)E(\hat{\theta}) = \frac{3}{2} - E(\overline{X})

E(θ^)=32E(X)E(\hat{\theta}) = \frac{3}{2} - E(X)

Substitute E(X)=23θE(X) = \frac{2}{3} \theta:

E(θ^)=3223θE(\hat{\theta}) = \frac{3}{2} - \frac{2}{3} \theta

Step 2: Check if θ^\hat{\theta} is unbiased

For θ^\hat{\theta} to be unbiased, E(θ^)E(\hat{\theta}) should equal θ\theta. So we check if:

E(θ^)=θE(\hat{\theta}) = \theta

From the previous calculation, we have:

E(θ^)=3223θE(\hat{\theta}) = \frac{3}{2} - \frac{2}{3} \theta

Equating this to θ\theta:

θ=3223θ\theta = \frac{3}{2} - \frac{2}{3} \theta

Multiply both sides by 3 to eliminate the fraction:

3θ=92θ3\theta = 9 - 2\theta

Add 2θ2\theta to both sides:

5θ=95\theta = 9

Solve for θ\theta:

θ=95\theta = \frac{9}{5}

Conclusion:

Since θ=95\theta = \frac{9}{5}, the estimator θ^\hat{\theta} is not unbiased unless θ=95\theta = \frac{9}{5}. Therefore, θ^\hat{\theta} is a biased estimator of θ\theta.


Would you like further clarification or more details on this result?

Here are 5 related questions:

  1. What conditions might make an estimator unbiased?
  2. How does bias affect the accuracy of an estimator?
  3. What is the difference between the method of moments (MOM) and maximum likelihood estimation (MLE)?
  4. How would we adjust θ^\hat{\theta} to make it unbiased?
  5. What is the variance of the estimator θ^\hat{\theta}?

Tip: A biased estimator can still be useful if it has low variance—this creates a trade-off known as the bias-variance trade-off in estimation theory.

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Math Problem Analysis

Mathematical Concepts

Estimation
Unbiasedness
Method of Moments
Statistics

Formulas

E(X) = (2/3) * theta
Theta hat (MOM) = 3/2 - (1/n) * sum(Xi)
E(Theta hat) = 3/2 - E(X)
E(X) = (2/3) * theta

Theorems

Unbiasedness theorem
Method of Moments Estimation

Suitable Grade Level

Undergraduate (Statistics)