Math Problem Statement

If f(x) = 8x + 16, then find f -1(x).

Solution

To find the inverse function f1(x)f^{-1}(x), follow these steps:

  1. Start with the given function: f(x)=8x+16f(x) = 8x + 16

  2. Replace f(x)f(x) with yy: y=8x+16y = 8x + 16

  3. Swap xx and yy to reflect the inverse: x=8y+16x = 8y + 16

  4. Solve for yy (which is now f1(x)f^{-1}(x)): x16=8yx - 16 = 8y y=x168y = \frac{x - 16}{8}

So, the inverse function is: f1(x)=x168f^{-1}(x) = \frac{x - 16}{8}

Would you like more details on inverse functions or any specific steps? Here are some related questions:

  1. How do you verify if two functions are inverses of each other?
  2. What is the domain and range of f(x)=8x+16f(x) = 8x + 16?
  3. How can you graph f(x)f(x) and its inverse f1(x)f^{-1}(x)?
  4. How do linear functions behave when their inverses are calculated?
  5. What happens if you try to find the inverse of a non-linear function?

Tip: To check if two functions are inverses, compose them (i.e., calculate f(f1(x))f(f^{-1}(x)) and f1(f(x))f^{-1}(f(x))). If both compositions give xx, the functions are inverses.

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Math Problem Analysis

Mathematical Concepts

Algebra
Inverse Functions
Linear Functions

Formulas

f^{-1}(x) = \frac{x - 16}{8}

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 9-11