Math Problem Statement

LetRbearelationfromasetAtoasetB.Theinverserela tionfromBtoA,denotedbyR−1,isthesetoforderedpairs {(b,a)|(a,b) ∈R}.ThecomplementaryrelationRisthe setoforderedpairs{(a,b)|(a,b)/ ∈R}.LetRbetherelationR={(a,b)|adividesb}ontheset ofpositiveintegers.Find a) R−1. b) R

Solution

Let's break down and solve the problem step by step. We are given that:

  • RR is a relation from set AA to set BB, and the relation is defined as R={(a,b)a divides b}R = \{(a, b) \mid a \text{ divides } b\}, where a,ba, b are positive integers.
  • We are asked to find the inverse relation R1R^{-1} and the complementary relation RcR^c.

Part (a) – Find R1R^{-1}

The inverse of a relation RR, denoted R1R^{-1}, consists of the ordered pairs (b,a)(b, a) such that (a,b)R(a, b) \in R. In other words, if aa divides bb in RR, then in R1R^{-1}, bb divides aa.

Thus, if (a,b)R(a, b) \in R, then aa divides bb. Therefore, for (b,a)R1(b, a) \in R^{-1}, we must have that bb divides aa.

So, the relation R1R^{-1} is:

R1={(b,a)b divides a}R^{-1} = \{(b, a) \mid b \text{ divides } a\}

Part (b) – Find RcR^c

The complementary relation RcR^c consists of all the ordered pairs (a,b)(a, b) such that (a,b)R(a, b) \notin R. In other words, RcR^c contains all pairs where aa does not divide bb.

Thus, the complementary relation RcR^c is:

Rc={(a,b)a does not divide b}R^c = \{(a, b) \mid a \text{ does not divide } b\}

Summary of Answers:

  • (a) The inverse relation R1R^{-1} is:

R1={(b,a)b divides a}R^{-1} = \{(b, a) \mid b \text{ divides } a\}

  • (b) The complementary relation RcR^c is:

Rc={(a,b)a does not divide b}R^c = \{(a, b) \mid a \text{ does not divide } b\}

Would you like more detailed explanations or examples of these relations?

Here are some related questions to expand on this topic:

  1. What is the difference between a relation and a function, and how does it apply to divisibility relations?
  2. How can we prove whether a relation is reflexive, symmetric, or transitive?
  3. How do we find the composition of relations, particularly with divisibility relations?
  4. What is the concept of an equivalence relation, and does the divisibility relation satisfy it?
  5. How do we represent a relation as a matrix and analyze its properties?

Tip: When working with relations, always carefully consider the properties (reflexivity, symmetry, transitivity) that can help in understanding and solving problems related to the relation.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Relations and Functions
Inverse Relations
Complementary Relations
Divisibility

Formulas

Inverse Relation: R^−1 = {(b, a) | (a, b) ∈ R}
Complementary Relation: R^c = {(a, b) | (a, b) ∉ R}

Theorems

Divisibility Rule: a divides b if there exists an integer k such that b = a * k

Suitable Grade Level

Grades 10-12