Math Problem Statement

The department of health wishes to estimate the weight of its people using the given data sample. Additionally, the hypothesis that the mean height of students in a university is 170 cm is tested using provided height data, assuming normal distribution and specified confidence levels.

Solution

The image you uploaded contains two tasks: one regarding interval estimation for weights and the other about hypothesis testing for the mean height of students. I'll break down how to solve these tasks step by step.

Task 1: Interval Estimation for Weights

We are given a data set of weights:

70,65,67,72,82,56,66,76,56,45,46,54,57,76,67,87,56,6570, 65, 67, 72, 82, 56, 66, 76, 56, 45, 46, 54, 57, 76, 67, 87, 56, 65

We need to estimate the population mean using the following confidence levels:

  • 90%
  • 95%

Steps for solving:

  1. Calculate the sample mean (xˉ\bar{x}) and the sample standard deviation (s).
  2. Find the Z-value corresponding to the confidence levels (for 90% and 95%).
  3. Calculate the confidence intervals using the formula:

CI=xˉ±Z×snCI = \bar{x} \pm Z \times \frac{s}{\sqrt{n}}

Where:

  • xˉ\bar{x} is the sample mean
  • ss is the sample standard deviation
  • nn is the sample size
  • ZZ is the Z-value from the Z-table corresponding to the confidence level.

Task 2: Hypothesis Testing for Heights

We are given a data set of heights:

169,164,166,171,181,155,165,175,155,144,145,153,156,175,166,186,155,164169, 164, 166, 171, 181, 155, 165, 175, 155, 144, 145, 153, 156, 175, 166, 186, 155, 164

We need to test the hypothesis that the mean height is 170 cm, using the following confidence levels:

  • 90%
  • 95%

Steps for solving:

  1. Set up the null hypothesis (H0H_0) and alternative hypothesis (H1H_1):

    • H0H_0: The mean height is 170 cm.
    • H1H_1: The mean height is not 170 cm.
  2. Calculate the sample mean (xˉ\bar{x}) and sample standard deviation (s).

  3. Perform a one-sample t-test since the sample size is small and we are assuming normality. Use the formula:

t=xˉμ0snt = \frac{\bar{x} - \mu_0}{\frac{s}{\sqrt{n}}}

Where:

  • xˉ\bar{x} is the sample mean
  • μ0\mu_0 is the hypothesized population mean (170 cm)
  • ss is the sample standard deviation
  • nn is the sample size
  1. Find the critical t-value corresponding to the confidence levels (90% and 95%).
  2. Compare the test statistic with the critical t-value to make a decision on whether to reject H0H_0.

Would you like me to compute these values for you or provide further details on how to approach these calculations?

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Math Problem Analysis

Mathematical Concepts

Interval Estimation
Confidence Intervals
Hypothesis Testing
Normal Distribution

Formulas

Confidence Interval Formula: CI = x̄ ± Z * (s / √n)
t-Test Formula: t = (x̄ - μ₀) / (s / √n)

Theorems

Central Limit Theorem
Properties of Normal Distribution

Suitable Grade Level

Undergraduate Level