Math Problem Statement
Solve from 9th question explaining every single calculation
Solution
Let’s solve the questions starting from Question 9. I'll break down each step of the calculations and provide clear explanations.
Question 9:
The cost function for units is given by:
We are asked to show that average variable cost (AVC) and marginal cost (MC) intersect at the minimum of the average variable cost.
Step 1: Definitions
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Total Cost (TC): Given as .
Here, is the fixed cost (constant term). -
Variable Cost (VC): Variable cost is the part of total cost dependent on , so:
-
Average Variable Cost (AVC):
Average Variable Cost is:
-
Marginal Cost (MC):
Marginal Cost is the derivative of total cost with respect to :
Step 2: Finding Intersection Point
To find the intersection of and , set :
Simplify by subtracting from both sides:
Factorize:
Thus, or .
Since is not feasible for production, the intersection occurs at:
Step 3: Verify Minimum Point
To verify that this is the minimum of , compute the derivative of :
Set for critical points:
Thus, is minimum at , which is the same point where .
Conclusion for Question 9:
The average variable cost (AVC) and marginal cost (MC) curves intersect at the minimum of the average variable cost curve.
Would you like to proceed with Question 10 or review any steps in this solution? Let me know!
Here are five related questions you might consider:
- What is the significance of the intersection of AVC and MC?
- How does fixed cost impact the cost functions?
- Why does reach a minimum?
- How does the shape of change for different values of ?
- Can AVC and MC fail to intersect for certain cost functions?
Tip: Always verify minimum/maximum points by checking the derivative's sign or the second derivative.
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Math Problem Analysis
Mathematical Concepts
Calculus
Cost Analysis
Optimization
Formulas
Total Cost: C(x) = ax^3 + bx^2 - cx + d
Variable Cost: VC(x) = ax^3 + bx^2 - cx
Average Variable Cost: AVC(x) = VC(x)/x = ax^2 + bx - c
Marginal Cost: MC(x) = d(C(x))/dx = 3ax^2 + 2bx - c
Theorems
Intersection of AVC and MC at minimum AVC point
Suitable Grade Level
Grades 11-12 or introductory college-level calculus
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