Math Problem Statement

Please integrate log(x^2 +1)/x. The answer will require the Li_2(x) function. Please proceed step by step.

Solution

To solve the integral of log(x2+1)xdx\frac{\log(x^2 + 1)}{x} \, dx, we proceed step by step and use special functions like the dilogarithm Li2(x)\text{Li}_2(x) when necessary. Here's how to tackle this problem:

Step 1: Recognize the structure of the integrand

We need to evaluate: I=log(x2+1)xdxI = \int \frac{\log(x^2 + 1)}{x} \, dx This integral is non-trivial and involves logarithmic and rational functions. To approach it, we can use substitution and the polylogarithmic functions, including the dilogarithm function Li2(x)\text{Li}_2(x).

Step 2: Substitution

Let's try the substitution: u=x2+1u = x^2 + 1 Then, we compute the differential of uu: du=2xdxdu = 2x \, dx Thus, xdx=du2x \, dx = \frac{du}{2} Rewriting the integral in terms of uu, we get: I=12log(u)u1duI = \frac{1}{2} \int \frac{\log(u)}{u - 1} \, du

Step 3: Express in terms of the dilogarithm function Li2(x)\text{Li}_2(x)

The integral log(u)u1du\int \frac{\log(u)}{u - 1} \, du is known to be related to the dilogarithm function Li2(x)\text{Li}_2(x). Specifically, we can use the following known result from integral tables or advanced calculus: log(u)u1du=Li2(1u)+log(u)log(u1)\int \frac{\log(u)}{u - 1} \, du = \text{Li}_2(1 - u) + \log(u) \log(u - 1)

Step 4: Substitute back u=x2+1u = x^2 + 1

Now that we have the result of the integral in terms of uu, we substitute back u=x2+1u = x^2 + 1: I=12(Li2(1(x2+1))+log(x2+1)log(x2))I = \frac{1}{2} \left( \text{Li}_2(1 - (x^2 + 1)) + \log(x^2 + 1) \log(x^2) \right) Simplifying: I=12(Li2(x2)+log(x2+1)2log(x))I = \frac{1}{2} \left( \text{Li}_2(-x^2) + \log(x^2 + 1) \cdot 2 \log(x) \right) I=12Li2(x2)+log(x)log(x2+1)I = \frac{1}{2} \text{Li}_2(-x^2) + \log(x) \log(x^2 + 1)

Step 5: Final answer

The final expression for the integral is: I=12Li2(x2)+2log(x)log(x2+1)+CI = \frac{1}{2} \text{Li}_2(-x^2) + 2 \log(x) \log(x^2 + 1) + C where CC is the constant of integration.


Would you like further details on any step? Here are related questions for additional practice:

  1. How can you apply the substitution method to simplify integrals involving logarithmic functions?
  2. What are some other integrals where the dilogarithm Li2(x)\text{Li}_2(x) function appears?
  3. How is the dilogarithm function defined and what are its properties?
  4. What other special functions, besides Li2(x)\text{Li}_2(x), arise in integral calculus?
  5. Can you compute the definite integral of log(x2+1)x\frac{\log(x^2 + 1)}{x} from x=1x = 1 to x=2x = 2?

Tip: Familiarize yourself with special functions like the dilogarithm function Li2(x)\text{Li}_2(x) as they often arise in advanced calculus and mathematical physics.

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Math Problem Analysis

Mathematical Concepts

Integration
Logarithmic Functions
Special Functions
Dilogarithm (Li_2(x))

Formulas

Substitution u = x^2 + 1, du = 2x dx
∫(log(u) / (u - 1)) du = Li_2(1 - u) + log(u)log(u - 1)
Final answer: (1/2) Li_2(-x^2) + 2 log(x) log(x^2 + 1) + C

Theorems

Dilogarithm Properties
Substitution in Integration

Suitable Grade Level

Undergraduate Calculus, Advanced Placement Calculus