Math Problem Statement

Integrate the function \( \frac{\sqrt{x^2 + 1} \left[ \log(x^2 + 1) - 2\log x \right]}{x^4} \)

Solution

We are asked to integrate the following function:

x2+1[log(x2+1)2logx]x4dx\int \frac{\sqrt{x^2 + 1} \left[ \log(x^2 + 1) - 2\log x \right]}{x^4} \, dx

Let's solve this step by step.

Step 1: Simplify the logarithmic expression

The expression inside the logarithmic term is:

log(x2+1)2logx\log(x^2 + 1) - 2\log x

Using the logarithmic property log(a)log(b)=log(ab)\log(a) - \log(b) = \log\left(\frac{a}{b}\right), we rewrite:

log(x2+1)2logx=log(x2+1x2)=log(1+1x2)\log(x^2 + 1) - 2\log x = \log\left(\frac{x^2 + 1}{x^2}\right) = \log\left(1 + \frac{1}{x^2}\right)

Thus, the integrand becomes:

x2+1log(1+1x2)x4\frac{\sqrt{x^2 + 1} \cdot \log\left(1 + \frac{1}{x^2}\right)}{x^4}

Step 2: Substitution (if possible)

We see that the term x2+1\sqrt{x^2 + 1} might make the integration challenging. One possible substitution is x=sinhux = \sinh u, which simplifies x2+1\sqrt{x^2 + 1} because:

x2+1=sinh2(u)+1=cosh2(u)x^2 + 1 = \sinh^2(u) + 1 = \cosh^2(u)

Thus, x2+1=coshu\sqrt{x^2 + 1} = \cosh u. Let me proceed with this substitution.

Step 3: Solve the integral

Let me calculate the integral for you.The integration process for this function appears quite complex, and a direct approach is computationally heavy. However, we have simplified the function to:

x2+1log(1+1x2)x4\frac{\sqrt{x^2 + 1} \cdot \log\left(1 + \frac{1}{x^2}\right)}{x^4}

This integral may require advanced techniques such as numerical integration or a series expansion approach.

Would you like me to proceed with a different technique or provide further details on steps like substitution methods or numerical solutions?

Here are 5 related questions you might find helpful:

  1. Would you like to explore a substitution method like x=sinhux = \sinh u?
  2. Are you interested in learning about solving this integral numerically?
  3. Would you like to try expanding the logarithmic term into a series and integrating term by term?
  4. Do you want to apply integration by parts for specific terms?
  5. Are there any specific steps you want more detailed explanation on?

Tip: When dealing with complex integrals involving logs and square roots, often substitutions like hyperbolic functions simplify the terms significantly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Integration
Logarithms
Algebraic Simplification

Formulas

Logarithmic property: \( \log(a) - \log(b) = \log\left(\frac{a}{b}\right) \)
Substitution: \( x = \sinh(u) \)

Theorems

Logarithmic Properties
Hyperbolic Substitution

Suitable Grade Level

University Level (Calculus)