Math Problem Statement

find the integral of x^2+2/x^3+4x^2

Solution

We aim to compute the integral of x2+2x3+4x2dx\frac{x^2 + 2}{x^3 + 4x^2} \, dx. Let’s proceed step by step:

Step 1: Simplify the integrand

Factorize the denominator: x3+4x2=x2(x+4).x^3 + 4x^2 = x^2(x + 4). Thus, the integral becomes: x2+2x2(x+4)dx.\int \frac{x^2 + 2}{x^2(x + 4)} \, dx.

Step 2: Separate the terms

Split the fraction into partial fractions: x2+2x2(x+4)=Ax+Bx2+Cx+4.\frac{x^2 + 2}{x^2(x + 4)} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 4}.

Multiply through by x2(x+4)x^2(x + 4) to find AA, BB, and CC: x2+2=Ax(x+4)+B(x+4)+Cx2.x^2 + 2 = A x(x + 4) + B(x + 4) + Cx^2.

Expanding this: x2+2=Ax2+4Ax+Bx+4B+Cx2.x^2 + 2 = A x^2 + 4A x + Bx + 4B + Cx^2.

Combine like terms: x2+2=(A+C)x2+(4A+B)x+4B.x^2 + 2 = (A + C)x^2 + (4A + B)x + 4B.

Equate coefficients:

  1. A+C=1A + C = 1 (coefficient of x2x^2),
  2. 4A+B=04A + B = 0 (coefficient of xx),
  3. 4B=24B = 2 (constant term).

From 4B=24B = 2: B=12.B = \frac{1}{2}.

From 4A+B=04A + B = 0: 4A+12=0    A=18.4A + \frac{1}{2} = 0 \quad \implies \quad A = -\frac{1}{8}.

From A+C=1A + C = 1: 18+C=1    C=98.-\frac{1}{8} + C = 1 \quad \implies \quad C = \frac{9}{8}.

Thus, the partial fraction decomposition is: x2+2x2(x+4)=18x+12x2+98x+4.\frac{x^2 + 2}{x^2(x + 4)} = \frac{-\frac{1}{8}}{x} + \frac{\frac{1}{2}}{x^2} + \frac{\frac{9}{8}}{x + 4}.

Step 3: Integrate each term

The integral becomes: x2+2x2(x+4)dx=18xdx+12x2dx+98x+4dx.\int \frac{x^2 + 2}{x^2(x + 4)} \, dx = \int \frac{-\frac{1}{8}}{x} \, dx + \int \frac{\frac{1}{2}}{x^2} \, dx + \int \frac{\frac{9}{8}}{x + 4} \, dx.

  1. First term: 18xdx=18lnx.\int \frac{-\frac{1}{8}}{x} \, dx = -\frac{1}{8} \ln|x|.

  2. Second term: 12x2dx=12x2dx=12(x1)=12x.\int \frac{\frac{1}{2}}{x^2} \, dx = \frac{1}{2} \int x^{-2} \, dx = \frac{1}{2} \left( -x^{-1} \right) = -\frac{1}{2x}.

  3. Third term: 98x+4dx=98lnx+4.\int \frac{\frac{9}{8}}{x + 4} \, dx = \frac{9}{8} \ln|x + 4|.

Step 4: Combine the results

The final integral is: x2+2x3+4x2dx=18lnx12x+98lnx+4+C,\int \frac{x^2 + 2}{x^3 + 4x^2} \, dx = -\frac{1}{8} \ln|x| - \frac{1}{2x} + \frac{9}{8} \ln|x + 4| + C, where CC is the constant of integration.

Let me know if you have questions or want any specific steps clarified. 😊

Follow-up Questions

  1. Would you like a more detailed explanation of the partial fraction decomposition process?
  2. Do you need help with integrating similar rational functions?
  3. Would you like me to explain the rules for solving definite integrals involving logarithms?
  4. Should I verify this solution with numerical integration?
  5. Would you like to see a graphical representation of the integrand?

Tip

Always check if the denominator can be factorized to simplify rational integrals using partial fractions!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Integral Calculus
Partial Fractions
Logarithmic Integration

Formulas

Partial fraction decomposition: A/x + B/x^2 + C/(x + 4)
Integration of 1/x: ∫(1/x) dx = ln|x| + C
Integration of x^n: ∫x^n dx = x^(n+1)/(n+1) + C, for n ≠ -1

Theorems

Fundamental Theorem of Calculus
Method of Partial Fractions

Suitable Grade Level

Grades 11-12 and early college