Math Problem Statement

How to do with u substituting

How to do with u substituting

Solution

To solve the given integral using uu-substitution:

01dxx+7x3\int_0^1 \frac{dx}{\sqrt{x} + 7\sqrt[3]{x}}

Step-by-Step Approach:

  1. Substitute u=x1/6u = x^{1/6}:

    • Then, x=u6x = u^6.
    • The derivative of xx is dx=6u5dudx = 6u^5 \, du.
    • Substituting u=x1/6u = x^{1/6}, we observe:
      • x=x1/2=(u6)1/2=u3\sqrt{x} = x^{1/2} = (u^6)^{1/2} = u^3,
      • x3=x1/3=(u6)1/3=u2\sqrt[3]{x} = x^{1/3} = (u^6)^{1/3} = u^2.
  2. Transform the integral: Rewriting the integral in terms of uu: 01dxx+7x3=016u5duu3+7u2.\int_0^1 \frac{dx}{\sqrt{x} + 7\sqrt[3]{x}} = \int_0^1 \frac{6u^5 \, du}{u^3 + 7u^2}.

  3. Simplify the expression: Factor u2u^2 from the denominator: 016u5duu3+7u2=016u5duu2(u+7).\int_0^1 \frac{6u^5 \, du}{u^3 + 7u^2} = \int_0^1 \frac{6u^5 \, du}{u^2(u + 7)}.

    Cancel u2u^2 from the numerator and denominator (ensuring u0u \neq 0): 016u5duu2(u+7)=016u3u+7du.\int_0^1 \frac{6u^5 \, du}{u^2(u + 7)} = \int_0^1 \frac{6u^3}{u + 7} \, du.

  4. Simplify further and integrate: The integral can be evaluated using partial fraction decomposition or directly with numerical tools. In this case, you would either:

    • Use substitution techniques to simplify further.
    • Approximate numerically if necessary.

Would you like a numerical solution, or shall I proceed with further simplification for exact computation? Let me know!


Relative Questions:

  1. How does the choice of u=x1/6u = x^{1/6} simplify the integral?
  2. What are the alternatives to uu-substitution in solving this integral?
  3. How do partial fraction decomposition techniques apply here?
  4. What are the benefits of symbolic computation for this integral?
  5. Could this integral be solved using definite integration numerically?

Tip: Choosing a substitution that aligns with the roots in the problem simplifies both the algebra and integral structure significantly.

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Math Problem Analysis

Mathematical Concepts

Integration
u-substitution
Definite Integrals

Formulas

Substitution u = x^(1/6), where dx = 6u^5 du
Simplifying square roots: sqrt(x) = u^3, cube roots: x^(1/3) = u^2

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Undergraduate Calculus