integral from 0 to 4 of (2x)/(sqrt(x*x + 9))dx using the substitution u = sqrt(x*x + 9)

To solve the integral \(\int_0^4 \frac{2x}{\sqrt{x^2 + 9}} \, dx\) using the substitution \( u = \sqrt{x^2 + 9} \), follow these steps:

### Step 1: Substitution
Given the substitution \( u = \sqrt{x^2 + 9} \), we first need to express \( du \) in terms of \( dx \).

\[
u = \sqrt{x^2 + 9}
\]
Square both sides:
\[
u^2 = x^2 + 9
\]
Differentiate both sides with respect to \( x \):
\[
2u \frac{du}{dx} = 2x
\]
This simplifies to:
\[
\frac{du}{dx} = \frac{x}{u}
\]
Therefore:
\[
du = \frac{x}{u} dx
\]
Substitute \( u = \sqrt{x^2 + 9} \) back:
\[
du = \frac{x}{\sqrt{x^2 + 9}} dx
\]
Now solve for \( dx \):
\[
dx = \frac{u \, du}{x}
\]
But since \( x = \sqrt{u^2 - 9} \) (from \( u^2 = x^2 + 9 \)), we can write:
\[
dx = \frac{u \, du}{\sqrt{u^2 - 9}}
\]

### Step 2: Rewrite the Integral
Now, substitute into the integral:

\[
\int_0^4 \frac{2x}{\sqrt{x^2 + 9}} \, dx = \int_{u(0)}^{u(4)} \frac{2\sqrt{u^2 - 9}}{u} \cdot \frac{u \, du}{\sqrt{u^2 - 9}}
\]

Simplify the expression:
\[
\int_{u(0)}^{u(4)} 2 \, du
\]

### Step 3: Update Limits of Integration
We need to change the limits of integration according to the substitution \( u = \sqrt{x^2 + 9} \):

- When \( x = 0 \): \( u(0) = \sqrt{0^2 + 9} = \sqrt{9} = 3 \).
- When \( x = 4 \): \( u(4) = \sqrt{4^2 + 9} = \sqrt{16 + 9} = \sqrt{25} = 5 \).

So the integral becomes:
\[
\int_3^5 2 \, du
\]

### Step 4: Integrate
Now, integrate with respect to \( u \):

\[
\int_3^5 2 \, du = 2u \Big|_3^5 = 2(5) - 2(3) = 10 - 6 = 4
\]

### Final Answer
The value of the integral is \( \boxed{4} \).

---

Would you like more details on any part of this solution? Here are some related questions that might interest you:

1. How do you handle substitution when the integral bounds change?
2. What are common substitutions for integrals involving square roots?
3. How does the choice of substitution affect the complexity of solving an integral?
4. What is the geometric interpretation of the integral \(\int_0^4 \frac{2x}{\sqrt{x^2 + 9}} dx\)?
5. How can we verify the correctness of an integral using differentiation?

**Tip:** Always double-check the limits of integration after performing a substitution, as they change with the new variable.

This page provides a detailed step-by-step solution to the integral from 0 to 4 of (2x)/(sqrt(x^2 + 9)) dx using the substitution method u = sqrt(x^2 + 9). The solution includes key concepts in calculus such as the substitution method and the Fundamental Theorem of Calculus. Suitable for students in Grades 11-12.

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