Math Problem Statement

Solve the following problems: 4. If x = (2,1 + i,i) and y = (2 - i,1,1 + 2i), then find ⟨x, y⟩. 5. In an inner product space R^3 with standard inner product let x = (1,2,-3) and y = (-1,4,-3). Check whether x and y are orthogonal or not. 6. In an inner product space R^4 with standard inner product if u = (3,2,k,-5) and v = (1,k,7,3) are orthogonal then find the value of k.

Solution

Let's work through the problems shown in the image step by step.

Problem 4:

You are given:

  • x=(2,1+i,i)x = (2, 1 + i, i)
  • y=(2i,1,1+2i)y = (2 - i, 1, 1 + 2i)

The goal is to find the inner product x,y\langle x, y \rangle.

For complex vectors, the inner product x,y\langle x, y \rangle is defined as:

x,y=k=1nxkyk\langle x, y \rangle = \sum_{k=1}^{n} x_k \cdot \overline{y_k} where yk\overline{y_k} is the complex conjugate of the corresponding element in yy.

Now compute step-by-step:

  • x1=2x_1 = 2 and y1=2iy_1 = 2 - i, so: x1y1=2(2+i)=4+2ix_1 \cdot \overline{y_1} = 2 \cdot (2 + i) = 4 + 2i
  • x2=1+ix_2 = 1 + i and y2=1y_2 = 1, so: x2y2=(1+i)1=1+ix_2 \cdot \overline{y_2} = (1 + i) \cdot 1 = 1 + i
  • x3=ix_3 = i and y3=1+2iy_3 = 1 + 2i, so: x3y3=i(12i)=i2i2=i+2=2+ix_3 \cdot \overline{y_3} = i \cdot (1 - 2i) = i - 2i^2 = i + 2 = 2 + i

Now sum them up: x,y=(4+2i)+(1+i)+(2+i)=7+4i\langle x, y \rangle = (4 + 2i) + (1 + i) + (2 + i) = 7 + 4i

Thus, x,y=7+4i\langle x, y \rangle = 7 + 4i.


Problem 5:

You are given:

  • x=(1,2,3)x = (1, 2, -3)
  • y=(1,4,3)y = (-1, 4, -3)

Check if xx and yy are orthogonal by verifying whether x,y=0\langle x, y \rangle = 0.

The inner product for real vectors is simply: x,y=x1y1+x2y2+x3y3\langle x, y \rangle = x_1 y_1 + x_2 y_2 + x_3 y_3 Now compute: x,y=(11)+(24)+(33)=1+8+9=16\langle x, y \rangle = (1 \cdot -1) + (2 \cdot 4) + (-3 \cdot -3) = -1 + 8 + 9 = 16

Since x,y=160\langle x, y \rangle = 16 \neq 0, the vectors xx and yy are not orthogonal.


Problem 6:

You are given:

  • u=(3,2,k,5)u = (3, 2, k, -5)
  • v=(1,k,7,3)v = (1, k, 7, 3)

Find the value of kk such that uu and vv are orthogonal, i.e., u,v=0\langle u, v \rangle = 0.

The inner product is: u,v=31+2k+k7+(5)3\langle u, v \rangle = 3 \cdot 1 + 2 \cdot k + k \cdot 7 + (-5) \cdot 3 Simplifying: u,v=3+2k+7k15=2k+7k12=9k12\langle u, v \rangle = 3 + 2k + 7k - 15 = 2k + 7k - 12 = 9k - 12 Set u,v=0\langle u, v \rangle = 0 to find kk: 9k12=0    9k=12    k=129=439k - 12 = 0 \implies 9k = 12 \implies k = \frac{12}{9} = \frac{4}{3}

Thus, k=43k = \frac{4}{3}.


Would you like details or have any questions on any of the steps?

Here are 5 related questions:

  1. How does the concept of orthogonality extend to higher-dimensional spaces?
  2. What is the difference between inner product spaces with real and complex vectors?
  3. Can two vectors be orthogonal if their components are complex numbers?
  4. What are the geometrical interpretations of the inner product?
  5. How can you apply the Cauchy-Schwarz inequality to check vector relationships?

Tip: When dealing with complex vectors, always remember to take the conjugate of the second vector in the inner product calculation.

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Math Problem Analysis

Mathematical Concepts

Inner Product
Complex Numbers
Orthogonality

Formulas

Inner product formula for real vectors: ⟨x, y⟩ = sum of corresponding elements products
Inner product formula for complex vectors: ⟨x, y⟩ = sum of x_k * conjugate(y_k)

Theorems

Orthogonality in Inner Product Spaces

Suitable Grade Level

Undergraduate - Linear Algebra