Math Problem Statement
Lucas had a bag of chocolates which was shared equally among 9 friends. Lucas ate 12 of them before sharing. Each friend got 5 chocolates. How many chocolates did Lucas have at the beginning?
Solution
Let's go through this step-by-step to find out how many chocolates Lucas originally had.
-
Determine the total number of chocolates shared:
Each of the 9 friends received 5 chocolates, so: Therefore, Lucas shared a total of 45 chocolates. -
Account for the chocolates Lucas ate:
Before sharing, Lucas ate 12 chocolates. This means that the total number of chocolates he had initially is the sum of the chocolates he shared and the ones he ate:
Answer:
Lucas originally had 57 chocolates.
Would you like more details on this solution, or do you have any questions?
Here are 5 related questions to explore further:
- If each friend had received 6 chocolates instead of 5, how many chocolates would Lucas have originally had?
- What if Lucas ate 15 chocolates before sharing—how many would he have started with?
- Suppose Lucas wanted to share the chocolates with 12 friends instead of 9; how would that affect the initial amount?
- How many chocolates would each friend get if Lucas shared them with 10 friends and ate 12 before sharing?
- If Lucas had shared the chocolates equally among 9 friends and kept 10 chocolates for himself, what was the initial count?
Tip: When working with word problems, list out each given quantity to help set up your equations clearly.
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Math Problem Analysis
Mathematical Concepts
Basic Algebra
Arithmetic
Word Problems
Formulas
Total Chocolates = Chocolates Shared + Chocolates Eaten
Theorems
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Suitable Grade Level
Grades 4-6
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