Math Problem Statement

x^2+2x+1 The function is increasing on the interval

Solution

To determine the interval on which the function f(x)=x2+2x+1f(x) = x^2 + 2x + 1 is increasing, we first find its derivative and analyze its behavior.

Step 1: Find the derivative

The derivative of f(x)=x2+2x+1f(x) = x^2 + 2x + 1 is: f(x)=2x+2f'(x) = 2x + 2

Step 2: Analyze the derivative

The function increases where the derivative is positive, that is, f(x)>0f'(x) > 0. Let's solve the inequality: 2x+2>02x + 2 > 0 2x>22x > -2 x>1x > -1

Conclusion:

The function f(x)=x2+2x+1f(x) = x^2 + 2x + 1 is increasing on the interval (1,)(-1, \infty).

Would you like a detailed explanation of how to find intervals where a function is increasing or decreasing?


Here are five related questions to deepen understanding:

  1. How do you find the decreasing intervals of a quadratic function?
  2. What is the minimum value of the function f(x)=x2+2x+1f(x) = x^2 + 2x + 1?
  3. Can you explain the role of the vertex in determining intervals of increase and decrease?
  4. How would you apply this method to a cubic function?
  5. How does the second derivative relate to concavity and intervals of increase or decrease?

Tip: Always check the sign of the first derivative to determine where a function is increasing or decreasing!

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Math Problem Analysis

Mathematical Concepts

Algebra
Calculus
Quadratic Functions
Derivatives

Formulas

f(x) = x^2 + 2x + 1
f'(x) = 2x + 2

Theorems

First Derivative Test

Suitable Grade Level

Grades 9-12