Math Problem Statement

Solve the initial value problem y 3 − 5x 4 − 3xy2 + e x = (3x 2 y − 3xy2 + y 2 + cos y)y 0 , y(0) = π 2 . Present your solution as a relation defining y implicitly as a function of x.

Solution

The given initial value problem is:

y35x43xy2+ex=(3x2y3xy2+y2+cosy)yy^3 - 5x^4 - 3xy^2 + e^x = \left( 3x^2 y - 3xy^2 + y^2 + \cos y \right) y'

with the initial condition y(0)=π2y(0) = \frac{\pi}{2}.

Step 1: Rearrange the equation

We start by rearranging the equation to separate the terms involving yy':

y35x43xy2+ex=(3x2y3xy2+y2+cosy)yy^3 - 5x^4 - 3xy^2 + e^x = \left( 3x^2 y - 3xy^2 + y^2 + \cos y \right) y'

Now, divide both sides by 3x2y3xy2+y2+cosy3x^2 y - 3xy^2 + y^2 + \cos y:

y=y35x43xy2+ex3x2y3xy2+y2+cosyy' = \frac{y^3 - 5x^4 - 3xy^2 + e^x}{3x^2 y - 3xy^2 + y^2 + \cos y}

Step 2: Integrate both sides

To solve for y(x)y(x) implicitly, we need to integrate both sides with respect to xx:

dyy35x43xy2+ex=dx3x2y3xy2+y2+cosy\int \frac{dy}{y^3 - 5x^4 - 3xy^2 + e^x} = \int \frac{dx}{3x^2 y - 3xy^2 + y^2 + \cos y}

However, this integral is highly non-trivial and not easily solvable by elementary functions. Instead, we use the given initial condition to write the implicit solution.

Step 3: Use the initial condition

Given y(0)=π2y(0) = \frac{\pi}{2}, the solution is implicitly defined by a function F(x,y)=CF(x, y) = C where CC is a constant determined by the initial condition.

The relation defining yy implicitly as a function of xx is given by:

F(x,y)=dyy35x43xy2+ex=CF(x, y) = \int \frac{dy}{y^3 - 5x^4 - 3xy^2 + e^x} = C

Substituting x=0x = 0 and y=π2y = \frac{\pi}{2}:

F(0,π2)=CF(0, \frac{\pi}{2}) = C

Thus, the solution is given implicitly by the relation:

dyy35x43xy2+ex=dx3x2y3xy2+y2+cosy+C\int \frac{dy}{y^3 - 5x^4 - 3xy^2 + e^x} = \int \frac{dx}{3x^2 y - 3xy^2 + y^2 + \cos y} + C

Where CC is determined by the initial condition F(0,π2)F(0, \frac{\pi}{2}).

This is the implicit form of the solution for the initial value problem.


Would you like further details or have any questions?

Here are some related questions:

  1. How do you solve implicit differential equations in general?
  2. What are the common methods for solving first-order differential equations?
  3. How do initial conditions affect the solution of differential equations?
  4. What are some numerical methods for solving differential equations when analytical solutions are complex?
  5. How do you interpret the results of an implicit solution?
  6. What is the significance of the constant of integration in differential equations?
  7. What techniques can simplify complex integrals in differential equations?
  8. Can differential equations always be solved explicitly?

Tip: For complex differential equations that are difficult to solve analytically, consider numerical methods like Euler's or Runge-Kutta.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Implicit Functions
Initial Value Problems
Integration

Formulas

Implicit differentiation
Initial value problem solutions
Integration techniques

Theorems

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Suitable Grade Level

Undergraduate level