Math Problem Statement

Given the functions, identify the odd functions among them.

Solution

The problem asks to identify which of the given functions are odd functions. Let's go through the functions step by step to check whether each one is odd.

Recall:

A function f(x)f(x) is odd if: f(x)=f(x)f(-x) = -f(x) This means that if you replace xx with x-x, the result must be the negative of the original function.

Now, let's analyze the functions:

1. y=x2y = x - 2

Substitute x-x for xx: f(x)=x2f(-x) = -x - 2

Clearly, f(x)(x2)=x+2f(-x) \neq -(x - 2) = -x + 2, so this function is not odd.

2. y=x3+5xy = x^3 + 5x

Substitute x-x for xx: f(x)=(x)3+5(x)=x35xf(-x) = (-x)^3 + 5(-x) = -x^3 - 5x

Now, check if this is the negative of the original function: (x3+5x)=x35x-(x^3 + 5x) = -x^3 - 5x

Since f(x)=f(x)f(-x) = -f(x), this function is odd.

3. y=x4y = \frac{x}{4}

Substitute x-x for xx: f(x)=x4=x4f(-x) = \frac{-x}{4} = -\frac{x}{4}

Check if this is the negative of the original function: x4=f(x)-\frac{x}{4} = -f(x)

Thus, this function is odd.

4. y=4x3x+2y = 4x^3 - x + 2

Substitute x-x for xx: f(x)=4(x)3(x)+2=4x3+x+2f(-x) = 4(-x)^3 - (-x) + 2 = -4x^3 + x + 2

Clearly, f(x)(4x3x+2)=4x3+x2f(-x) \neq -(4x^3 - x + 2) = -4x^3 + x - 2, so this function is not odd.

Conclusion:

Among the given functions, the odd functions are:

  • y=x3+5xy = x^3 + 5x
  • y=x4y = \frac{x}{4}

Would you like further details or clarification on any step?

Here are 5 related questions to explore further:

  1. What are the properties of even functions?
  2. How can we graphically identify odd functions?
  3. Can a function be both even and odd?
  4. How does symmetry relate to odd functions?
  5. Can a polynomial of even degree be an odd function?

Tip: Odd functions have rotational symmetry about the origin, which can help when sketching or analyzing graphs!

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Math Problem Analysis

Mathematical Concepts

Function analysis
Symmetry in functions

Formulas

f(-x) = -f(x)

Theorems

Odd function property

Suitable Grade Level

Grades 9-12