Math Problem Statement

how to determine if a function is even or odd

Solution

To determine whether a function is even, odd, or neither, you can follow these steps:

1. Even Function Test:

A function f(x)f(x) is even if it satisfies the condition: f(x)=f(x)f(-x) = f(x) This means that the function's graph is symmetric about the y-axis.

2. Odd Function Test:

A function f(x)f(x) is odd if it satisfies the condition: f(x)=f(x)f(-x) = -f(x) This means that the function's graph is symmetric about the origin.

Steps to check:

  • Step 1: Substitute x-x into the function, i.e., find f(x)f(-x).
  • Step 2: Compare f(x)f(-x) with f(x)f(x) and f(x)-f(x).
    • If f(x)=f(x)f(-x) = f(x), the function is even.
    • If f(x)=f(x)f(-x) = -f(x), the function is odd.
    • If neither condition holds, the function is neither even nor odd.

Example 1: f(x)=x2f(x) = x^2

  • f(x)=(x)2=x2f(-x) = (-x)^2 = x^2
  • Since f(x)=f(x)f(-x) = f(x), the function is even.

Example 2: f(x)=x3f(x) = x^3

  • f(x)=(x)3=x3f(-x) = (-x)^3 = -x^3
  • Since f(x)=f(x)f(-x) = -f(x), the function is odd.

Example 3: f(x)=x2+xf(x) = x^2 + x

  • f(x)=(x)2+(x)=x2xf(-x) = (-x)^2 + (-x) = x^2 - x
  • Since f(x)f(x)f(-x) \neq f(x) and f(x)f(x)f(-x) \neq -f(x), the function is neither even nor odd.

Would you like more details on this topic?

Here are 5 related questions for deeper understanding:

  1. What are examples of neither even nor odd functions?
  2. How do you determine if a piecewise function is even or odd?
  3. Can a function be both even and odd?
  4. How does symmetry in graphs help determine if a function is even or odd?
  5. What are the practical applications of even and odd functions in real-world problems?

Tip: When checking for symmetry, sketching the graph of the function can help visually confirm whether it is even, odd, or neither.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Symmetry in Graphs

Formulas

Even Function: f(-x) = f(x)
Odd Function: f(-x) = -f(x)

Theorems

Even and Odd Function Symmetry Theorem

Suitable Grade Level

Grades 9-12