Math Problem Statement

The graph of y = f(x) is shown in the xy-plane below. Which of the following equations could define f(x)? Options: A) f(x) = x^2 - 2x - 8 B) f(x) = -x^2 + 2x - 8 C) f(x) = (x - 2)(x + 4) D) f(x) = -(x - 1)^2 - 9

Solution

To solve this problem, we need to identify which of the given equations matches the graph of the function f(x)f(x) shown.

Step 1: Identify key features of the graph

  • Vertex: The graph has its vertex at the point (1,9)(1, -9).
  • Direction: The graph opens upwards, which indicates that the leading coefficient of x2x^2 is positive.
  • X-Intercepts: The graph crosses the x-axis at x=2x = -2 and x=4x = 4.

Step 2: Analyze the given options

  1. Option A: f(x)=x22x8f(x) = x^2 - 2x - 8

    • This is in standard form ax2+bx+cax^2 + bx + c.
    • To find the vertex, use the vertex formula x=b2a=22×1=1x = -\frac{b}{2a} = -\frac{-2}{2 \times 1} = 1.
    • Plugging x=1x = 1 into the equation: f(1)=122(1)8=128=9f(1) = 1^2 - 2(1) - 8 = 1 - 2 - 8 = -9.
    • The vertex is (1,9)(1, -9), which matches the graph.
    • To check the x-intercepts, set f(x)=0f(x) = 0: x22x8=0x^2 - 2x - 8 = 0 Factor the equation: (x4)(x+2)=0(x - 4)(x + 2) = 0 So the x-intercepts are x=4x = 4 and x=2x = -2, which match the graph.
  2. Option B: f(x)=x2+2x8f(x) = -x^2 + 2x - 8

    • This opens downwards due to the negative sign in front of x2x^2, which does not match the graph.
  3. Option C: f(x)=(x2)(x+4)f(x) = (x - 2)(x + 4)

    • This factored form has roots at x=2x = 2 and x=4x = -4, which do not match the graph's intercepts.
  4. Option D: f(x)=(x1)29f(x) = -(x - 1)^2 - 9

    • This is in vertex form with the vertex at (1,9)(1, -9), but it opens downwards (due to the negative sign in front), so it does not match the graph.

Conclusion

The correct equation that matches the graph is Option A: f(x)=x22x8f(x) = x^2 - 2x - 8.

Would you like more details on any specific part of the solution? Here are some related questions you might find helpful:

  1. How do you convert a quadratic equation from standard form to vertex form?
  2. What are the properties of parabolas based on the sign of the leading coefficient?
  3. How do you find the x-intercepts of a quadratic function?
  4. What is the significance of the vertex in the graph of a quadratic function?
  5. How can you determine if a parabola opens upwards or downwards?

Tip: To quickly determine the vertex of a parabola in standard form, use the formula x=b2ax = -\frac{b}{2a} to find the x-coordinate of the vertex.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Parabolas

Formulas

Standard form of a quadratic equation: ax^2 + bx + c = 0
Vertex form of a quadratic equation: a(x-h)^2 + k

Theorems

Vertex Formula: x = -b/2a
Factoring of Quadratic Equations

Suitable Grade Level

Grades 9-11