Math Problem Statement

Determine la regla de correspondencia de la función cuadrática g mostrada en la figura y los puntos que intercepta su gráfico con los ejes coordenados.

Solution

To determine the equation of the quadratic function gg shown in the graph and find its intercepts with the coordinate axes, let's analyze the key points and features of the parabola.

Step 1: Identify the Form of the Function

A quadratic function can generally be written as: g(x)=ax2+bx+cg(x) = ax^2 + bx + c Alternatively, if we have the vertex and another point, we can use the vertex form: g(x)=a(xh)2+kg(x) = a(x - h)^2 + k where (h,k)(h, k) is the vertex.

Step 2: Find the Vertex

From the graph:

  • The vertex appears to be at (3,4)(-3, -4).
    • This suggests that the equation can take the form g(x)=a(x+3)24g(x) = a(x + 3)^2 - 4.

Step 3: Identify Another Point on the Curve

Another clearly marked point is the y-intercept at (0,2)(0, 2). Substituting this point into the equation will help us find aa: 2=a(0+3)242 = a(0 + 3)^2 - 4 2=9a42 = 9a - 4 9a=69a = 6 a=23a = \frac{2}{3}

Step 4: Write the Equation

Now that we have a=23a = \frac{2}{3}, the equation of the function g(x)g(x) is: g(x)=23(x+3)24g(x) = \frac{2}{3}(x + 3)^2 - 4

Step 5: Find the Intercepts

  1. Y-Intercept: We've already identified this as (0,2)(0, 2).
  2. X-Intercepts: Set g(x)=0g(x) = 0 and solve for xx: 0=23(x+3)240 = \frac{2}{3}(x + 3)^2 - 4 23(x+3)2=4\frac{2}{3}(x + 3)^2 = 4 (x+3)2=6(x + 3)^2 = 6 x+3=±6x + 3 = \pm \sqrt{6} x=3±6x = -3 \pm \sqrt{6} So the x-intercepts are x=3+6x = -3 + \sqrt{6} and x=36x = -3 - \sqrt{6}.

Summary

  • The equation of the quadratic function is: g(x)=23(x+3)24g(x) = \frac{2}{3}(x + 3)^2 - 4
  • The intercepts are:
    • Y-intercept at (0,2)(0, 2)
    • X-intercepts at (3+6,0)\left( -3 + \sqrt{6}, 0 \right) and (36,0)\left( -3 - \sqrt{6}, 0 \right)

Would you like more details or have any questions?


Related Questions:

  1. How can you convert a quadratic function from vertex form to standard form?
  2. What are some other methods for finding the intercepts of a quadratic function?
  3. How does changing the value of aa affect the shape of a parabola?
  4. What is the axis of symmetry for this parabola, and how can it be derived?
  5. How can the quadratic formula be used to find the roots of a function in standard form?

Tip:

When you know the vertex and another point, using the vertex form of a quadratic equation is a quick and efficient way to find the function's rule.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Coordinate Geometry

Formulas

Quadratic equation in vertex form: g(x) = a(x - h)^2 + k
Standard form of a quadratic equation: ax^2 + bx + c = 0

Theorems

Vertex Theorem
Intercepts

Suitable Grade Level

Grades 9-12