To find the correct test statistic, you need to use the formula for the z-test for a proportion:

$z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where:

• $\hat{p} =$ sample proportion = $\frac{199}{797} \approx 0.25$
• $p_0 =$ population proportion = 0.37
• $n =$ sample size = 797

Plug these values into the formula:

$z = \frac{0.25 - 0.37}{\sqrt{\frac{0.37(1-0.37)}{797}}}$

Calculate the standard error:

$\text{SE} = \sqrt{\frac{0.37 \times 0.63}{797}} \approx 0.01747$

Calculate the z-score:

$z = \frac{0.25 - 0.37}{0.01747} \approx -6.88$

So the correct test statistic, rounded to two decimals, is approximately $-6.88$.