Math Problem Statement

Test the hypothesis that the population mean bail (mu) is 50.

To do that with Rcmdr/EZR, go to: Statistical analysis -> Continuous variables -> Single sample t-test , choose the variable, and enter your H0 and H1.

Set alpha (α) = 0.05.

Test statistic = 1.968376 Correct

df (if not applicable, put 0) = 21 Correct

What type of test statistic is this?

t Correct

p-value = 0.06236669 Correct

Decision: Fail to reject H0 Correct

We are 95% confident that the population parameter is somewhere in the interval: 22 Incorrect < μ < 50 Incorrect

What does all this tell us, in plain English? Is it reasonable to conclude that the population mean is $50? yes Correct

Could we have made a Type I error, or a Type II error, or is it impossible that we made any error at all (neither)? can you answer the part where it says "We are 95% confident that the population parameter is somewhere in the interval:"

Solution

To determine the confidence interval for the population mean (μ) based on your test results, we need to use the t-distribution because you're conducting a single sample t-test.

Given your information:

  • Test statistic (t) = 1.968376
  • Degrees of freedom (df) = 21
  • p-value = 0.06236669
  • Significance level (α) = 0.05

Confidence Interval Calculation

  1. Find the critical t-value: For a 95% confidence interval and 21 degrees of freedom, look up the critical t-value. This is approximately ±2.080 (you can use a t-table or statistical software).

  2. Calculate the standard error (SE): If you have the sample standard deviation (s) and sample size (n), you can calculate SE using: SE=snSE = \frac{s}{\sqrt{n}}

  3. Calculate the margin of error (ME): ME=tα/2×SEME = t_{\alpha/2} \times SE

  4. Construct the confidence interval: Confidence Interval=xˉ±ME\text{Confidence Interval} = \bar{x} \pm ME Where xˉ\bar{x} is the sample mean.

Interpretation

With a confidence interval, we are stating that we are 95% confident that the true population mean (μ) lies within the calculated interval. If the interval does not include $50, it suggests that the population mean could be different from this value.

Your Statement

Since you mentioned the interval as "22 < μ < 50" but labeled it incorrect, you will need to correctly calculate the confidence interval based on the sample data.

Conclusion

  1. Is it reasonable to conclude that the population mean is $50? Yes, since we fail to reject H0, it's reasonable, but it's still uncertain based on the confidence interval.

  2. Type of error: Since you failed to reject H0, a Type I error (rejecting a true null hypothesis) is not applicable. However, a Type II error (failing to reject a false null hypothesis) could be possible, given that the p-value is close to the significance level.

Questions for Further Exploration

  1. What is the sample size (n) and sample standard deviation (s) used in your test?
  2. Can you provide the sample mean (xˉ\bar{x}) to calculate the confidence interval accurately?
  3. How would you interpret a confidence interval that includes $50 versus one that does not?
  4. What are the implications of failing to reject H0 in your analysis?
  5. How would the results change if you had set a different significance level (e.g., α = 0.01)?

Tip

Always verify your calculations for the confidence interval, as it can provide critical insights into the validity of your hypothesis testing results.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Confidence Interval
Single Sample t-test
Statistical Significance
Type I and Type II Errors

Formulas

t = (x̄ - μ) / (s / √n)
Confidence Interval = x̄ ± t* × SE
Standard Error (SE) = s / √n

Theorems

Central Limit Theorem
t-Distribution Properties

Suitable Grade Level

Undergraduate Statistics