Math Problem Statement

What is the P value Question content area top Part 1 A simple random sample of size nequals15 is drawn from a population that is normally distributed. The sample mean is found to be x overbarequals21.8 and the sample standard deviation is found to be sequals6.3. Determine if the population mean is different from 24 at the alpha equals 0.01 level of significance.

Solution

To determine if the population mean (μ\mu) is different from 24 at the α=0.01\alpha = 0.01 level of significance, we perform a hypothesis test using the t-test for a single sample.


Step 1: State the Hypotheses

  • Null Hypothesis (H0H_0): μ=24\mu = 24 (the population mean is 24).
  • Alternative Hypothesis (HaH_a): μ24\mu \neq 24 (the population mean is different from 24).

Step 2: Calculate the Test Statistic

The formula for the test statistic is: t=xˉμ0s/nt = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} Where:

  • xˉ=21.8\bar{x} = 21.8 (sample mean),
  • μ0=24\mu_0 = 24 (hypothesized population mean),
  • s=6.3s = 6.3 (sample standard deviation),
  • n=15n = 15 (sample size).

Substituting the values: t=21.8246.3/15=2.26.3/3.873=2.21.6261.35t = \frac{21.8 - 24}{6.3 / \sqrt{15}} = \frac{-2.2}{6.3 / 3.873} = \frac{-2.2}{1.626} \approx -1.35


Step 3: Determine the Critical Value

Degrees of freedom (dfdf) for this test are: df=n1=151=14df = n - 1 = 15 - 1 = 14

For a two-tailed test at α=0.01\alpha = 0.01, we look up the critical tt-values in a tt-distribution table. With df=14df = 14: tcritical=±2.977t_{\text{critical}} = \pm 2.977


Step 4: Make a Decision

  • The calculated tt-statistic is 1.35-1.35, and it does not exceed the critical values (2.977-2.977 and +2.977+2.977).
  • Therefore, we fail to reject the null hypothesis.

Step 5: Calculate the P-value

To find the p-value, we use the cumulative probability for t=1.35t = -1.35 with df=14df = 14. Using a t-table or software, the p-value is approximately: P=0.197P = 0.197

Since P>αP > \alpha (0.197 > 0.01), we fail to reject the null hypothesis.


Conclusion

At the α=0.01\alpha = 0.01 level of significance, there is not enough evidence to conclude that the population mean is different from 24.


Would you like more details on any part of this process? Here are some related questions to explore:

  1. How is the critical tt-value determined in a two-tailed test?
  2. What happens if the sample size increases? How does it affect the tt-value?
  3. Can you explain the difference between the pp-value and α\alpha?
  4. What assumptions are required for a valid t-test?
  5. How would the test change if the population variance were known?

Tip: Always check that your data satisfies the conditions for a t-test, including normality and random sampling!

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
t-Test
Significance Level
P-Value

Formulas

t = (x̄ - μ₀) / (s / √n)
Degrees of freedom (df) = n - 1

Theorems

t-Distribution

Suitable Grade Level

Grades 11-12, Undergraduate Introductory Statistics